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GenaCL600 [577]
3 years ago
15

The cost of a pen and a pencil used to be the same, but recently the cost of the pen was increased by ₹4, whereas, the cost of p

encil became ₹6 less than 5 times its original value. After the revised cost, if the pen was more expensive than the pencil, what could have been the possible original value of both the products, if the initial price was a natural number?
Mathematics
1 answer:
erastova [34]3 years ago
6 0

Answer:

The possible original values of both products are ₹2 or ₹1

Step-by-step explanation:

The question is a word problem leading to simultaneous equations

Let 'x' represent the initial value of the pen and pencil

Therefore;

The final cost of the pen = x + ₹4

The final cost of the pencil = 5·x - ₹6

x + ₹4 > 5·x - ₹6

∴  ₹4 + ₹6 > 5·x - x

₹10 > 4x

₹10/4 > x

₹2.5 > x

Given that x is a natural number, therefore

x ≤ ₹2

The possible original values of both products are ₹2 or ₹1

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Answer is C if I'm not mistaken if its wrong let me know
4 0
3 years ago
What percent of 500 is 335
Nataly_w [17]

Here is your answer:

In order to find the answer divide the numerator by the denominator then divide that by one hundred:

  • 100%/x%=500/335
  • (100/x)*x=(500/335)*x
  • 100=1.49253731343*x
  • (1.49253731343)
  • 100/1.49253731343=x
  • x=67

Therefore "335 is 67% of 500."

Hope this helps!

8 0
3 years ago
Can someone help me, please
katrin [286]

Answer:

3. 108.982 feet per second

so yes faster than 100 feet per second

4.

5. 46.336°

6. 31.999°

7. 73.301°

8. 18.435°

Step-by-step explanation:

3. tan(16)= 250/x

x=250/tan(16)

x= 871.853611

speed=871.853611/8

= 108.982 feet per second

so yes faster than 100 feet per second

4. I do not understand the formulation of the question

5. sinx= 3.4/4.7

asin*(to the power of -1)*(3.4/4.7)=x

x=46.336

6.tanx=4,532/7253

atan*(power -1)* (4,532/7253)=x

x=31.999

7.tanx=500/150

x=73.301

8. tanx=30/10

atan(30/10)=x

x=71.56505118

90-71.56505118=18.43494882(the final angle)

5 0
3 years ago
Please help me there are 3 more questions please
Irina-Kira [14]

Answer:

Question 1: C) <5

Question 2: B) 139

Step-by-step explanation:

Question 1: They are looking for an angle with the same degrees as angle 4. There are for angles that have that, 1,4,5,8. When looking for the answer there is only one answer that fits in with those numbers, and that is answer C) <5.

Question 2: They provide us with the first angle of 139 degrees. Angle N corresponds with the first angle. Therefore angle N must be the same as the first angle, equaling 139 degrees.

8 0
3 years ago
Please solve for y. 3/4y= 7/8
Travka [436]
\frac{3}{4}y =  \frac{7}{8} \\ \\  \frac{3y}{4} =  \frac{7}{8} \\ \\ 3y =  \frac{7}{8} \times 4 \\ \\ 3y =  \frac{28}{8} \\ \\ 3y =  \frac{7}{2} \\ \\ y =  \frac{7}{2 \times 3} \\ \\ y =  \frac{7}{6} \\ \\

The final result is: y = 7/6.

4 0
3 years ago
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