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Dima020 [189]
3 years ago
7

An isosceles right triangle has an area 8 cm square find the length of its hypotenuse​

Mathematics
1 answer:
Ainat [17]3 years ago
6 0

Answer:

5.9

Step-by-step explanation:

Area of a triangle is 1/2 base times height. the base is the horizontal part of the triangle and the height is the vertical part. Since it a isosceles they are equal. Those two segment are also called the legs (remember that for later). 4x4=16 times 1/2 equal 8 cm squared. So know me must find the hypotenuse. Since we since dealing with a right triangle we are going to use pythagorean theorem which is

{a}^{2}  +  {b}^{2} =  {c}^{2}

where a and b are the LEGS and c is the hypotenuse. the legs are also known as base and height so we use

{4}^{2}  +  {4}^{2}  =  {c}^{2}

which simplify to

16 + 16  =  {c}^{2}

32 =  {c}^{2}

\sqrt{32}

which is about 5.9

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An isosceles triangle has an angle that measures 38degrees. What measures are possible for the other two angles? Choose all that
Sphinxa [80]

Answer:

  • 71° and 71°.

⠀

Step-by-step explanation:

The triangle having two sides equal along with one different side is called an isosceles triangle.

⠀

  • So, Let us assume the other sides (two equal sides) of the isosceles triangle as x. As the different side is already given in the question.

⠀

We know that,

  • The sum of all angles of a triangle is 180°

⠀

So, According to the question :

⠀

{\longrightarrow \it\qquad { \ { {  38 \: }^{ \circ}   + x + x  =  180{}^{ \circ} }}}

⠀

{\longrightarrow \it\qquad { \ { {  38 \: }^{ \circ}   + 2x   =  180{}^{ \circ} }}}

⠀

{\longrightarrow \it\qquad { \ {   2x   =  180{}^{ \circ} - {  38 \: }^{ \circ}}}}

⠀

{\longrightarrow \it\qquad { \ {   2x   =  142{}^{ \circ}  }}}

⠀

{\longrightarrow \it\qquad { \ {   x   =    \dfrac{142{}^{ \circ}}{2}   }}}

⠀

{\longrightarrow \it\qquad { \pmb {   x   =  71^{ \circ}  }}}

⠀

Therefore,

  • The measure of the two other angles of the isosceles triangle are 71° and 71°.
3 0
2 years ago
ACTIVITY 1: What a Difference!
arsen [322]

Answer:

1. -2

2.-10

3. 16

4. -29

5. 3

6. 11

7. 3

8. -4

9. 14

10. 25

4 0
3 years ago
Determine the simple interest rate for each given principal, time, and simple interest earned.
Akimi4 [234]

Answer:

31.8%

Step-by-step explanation:

The formula for simple interest is I = PRT, where I = interest earned/paid, P = principal amount deposited or borrowed, R = rate of interest as a decimal, and T = time in years.

I = PRT

5720 = (1200)(R)(15)

5720 = 18,000R

R = 0.3177777, rounded to 31.8%

5 0
3 years ago
Read 2 more answers
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Sindrei [870]
It is the second answer
4 0
3 years ago
Read 2 more answers
Help me with question a please ! With full workings !
frosja888 [35]
A)


\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
%  (c,d)
P&({{ 0.5}}\quad ,&{{ 0}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}

\bf QP=\sqrt{(0.5-0)^2+(0-2)^2}\implies QP=\sqrt{0.5^2+2^2}
\\\\\\
QP=\sqrt{\left( \frac{1}{2} \right)^2+4}\implies QP=\sqrt{ \frac{1^2}{2^2}+4}\implies QP=\sqrt{\frac{1}{4}+4}
\\\\\\
QP=\sqrt{\frac{17}{4}}\implies QP=\cfrac{\sqrt{17}}{\sqrt{4}}\implies QP=\cfrac{\sqrt{17}}{2}

b)

since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP

thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)


c)

what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
%   (c,d)
R&({{ -0.5}}\quad ,&{{ 0}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-2}{-0.5-0}\implies \cfrac{-2}{-0.5}

\bf m=\cfrac{\frac{-2}{1}}{-\frac{1}{2}}\implies \cfrac{-2}{1}\cdot \cfrac{2}{-1}\implies 4
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=4(x-0)\implies y=4x+2\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
7 0
3 years ago
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