Question

Kelsie sold digital cameras on her website. She bought the cameras for $65 each and included a 60% markup to get the selling price. To the nearest dollar, what was the selling price for one camera?

Answer 1

Answer:

$104.

Step-by-step explanation:

We have been given that Kelsie bought the cameras for $65 each and included a 60% markup to get the selling price.

The selling price of one camera will be equal to the cost of camera plus markup that is $65 plus 60% of $65.

$\text{Selling price of one camera}=\ 65+(\frac{60}{100}\times \ 65)$

$\text{Selling price of one camera}=\ 65+(0.60\times \ 65)$

$\text{Selling price of one camera}=\ 65+\ 39$

$\text{Selling price of one camera}=\ 104$

Therefore, the selling price of each camera is $104.

Answer 2

Find 60% of 65 then add it to 65:

0.6 * 65 = 39

Now add it to 65:

39 + 65 = 104

So she's selling camera's for $104 each.