The area of the square is 81 sq in, and the area of the circule is (3.14)(3 in)^2, or approx 3.14(9) sq in, or approx 28.27 sq in.
Subtract: 81 sq in - 28.27 sq in = approx. 52.73 sq in.
The difference is 52.73 sq in; the square is larger, the circle smaller.
The cost of one French silk cheesecake is $5 and one apple cheesecake is $14.
Step-by-step explanation:
Let,
Cost of one French silk cheesecake = x
Cost of one apple cheesecake = y
According to given statement;
8x+y=54 Eqn 1
3x+y=29 Eqn 2
Subtracting Eqn 2 from Eqn 1
Dividing both sides by 5
Putting x=5 in Eqn 1
The cost of one French silk cheesecake is $5 and one apple cheesecake is $14.
Keywords: linear equation, subtraction
Learn more about linear equations at:
#LearnwithBrainly
how much did they sale? you can not complete the answer without a sale amount. because you are asking that they made $1,200 plus 3% of sale, but you do not have the amount they sold so it just $1,200+3% of the sale , but no number for how much they sale, but for advice i would get the total amount they sale and divide by 100 then times it by 3 then try to fill in the void on how they went from 1,200 to 2500. You need to tell us the amount they sold and then the we can answer your question, but without you will not get your answer, so your question is incomplete.
Answer:
<u>Given rhombus ABCD with</u>
- m∠EAD = 67°, CE = 5, DE = 12
<u>Properties of a rhombus:</u>
- All sides are congruent
- Diagonals are perpendicular
- Diagonals are angle bisectors
- Diagonals bisect each other
<u>Solution, considering the above properties</u>
- 1. m∠AED = 90°, as angle between diagonals
- 2. m∠ADE = 90° - 67° = 23° as complementary of ∠EAD
- 3. m∠BAE = 67°, as ∠BAE ≅ ∠EAD
- 4. AE = CE = 5, as E is midpoint of AC
- 5. BE = DE = 12, as E is midpoint of BD
Answer:
To find a complex conjugate, simply change the sign of the imaginary part (the part with the i). This means that it either goes from positive to negative or from negative to positive.
As a general rule, the complex conjugate of <span>a+bi</span> is <span>a−bi</span>.
Therefore, the complex conjugate of <span>3−2i</span> is <span>3+2i</span>.
Hope this helped!!... :D
Please correct me if I'm wrong!!.. :3
