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SashulF [63]
4 years ago
7

What is the surface area of a square pyramid with a slant height of 6cm and the length of one side of the square base is 5cm

Mathematics
1 answer:
erica [24]4 years ago
4 0

Answer:

S = 85cm^2

Step-by-step explanation:

The surface area of a square pyramid is given by the following formula:

S=2hb+b^2

where it has taken into account the sum of the area of a square and four triangles:

4(\frac{hb}{2})+b*b=2bh+b^2

h: slant height = 6cm

b: base = 5cm

By replacing in the formula you obtain:

S=2(5cm)(6cm)+(5cm)^2=85cm^2

hence, the surface area is 85cm^2

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By using the rules that the value inside square root can’t be negative and the denominator value can’t be zero, the domain for the given function is a) x<-1 and x>1  b) p≤1/2  c) s>-1.

I found the complete question on Chegg, here is the full question:

Write the restrictions that should be imposed on the variable for each of the following function. Then find, explicitly, the domain for each function and write it in the interval notation a) f(x)=(x-2)/(x-1)  b) g(p)=√(1-2p)  c) m(s)= (s^2+4s+4)/√(s+1)

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a) For this case the denominator x-1 can not be zero. So, x ≠1 and the domain is x<-1 and x>1.

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Learn more about square root here:

brainly.com/question/3120622

#SPJ4

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