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daser333 [38]
4 years ago
7

I need help with this promblem and I need a answer and a good explaination on this thx!

Mathematics
2 answers:
salantis [7]4 years ago
5 0
It would be 7 because he gets in an accident every other time he gets a ticket
vladimir2022 [97]4 years ago
5 0
First work out the slope of the line
slope = rise / run   if you look at the pointt level with accidents  is  you see that rise / run - = 3.5 / 7  which is 0.5
The intercept on vertical axis is 1.5 
so we can write the equation of the line ( y = mx + b) where m = slope and b = y intercept) as  y = 0.5x + 1.5   ( y = accidents and x = number tickets)

so if we plug x = 10 (tickets) into the above 

Accidents ( for 10 tickets) = 0.5(10) + 1.5 = 6.5 which we round up to 7.
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Help me find the mode
DochEvi [55]

Answer:

28

Step-by-step explanation:

The value with maximum frequency is mode.

so here 28 is mode because it is repeates maximum number of times.

5 0
3 years ago
In the following distribution, P(X<2) = 0.35, and expected value is 1.9
Flauer [41]

Solution :

We have :

X            0     1          2    3   4

P(X)     0.10   A    0.35   B    C

a). P(X < 2) = 0.35

P(X < 2) = P(X = 0) + P(X = 1) = 0.35

⇒ 0.10 + A = 0.35

⇒ A = 0.25

So the value of A is 0.25

b). The total probability = 1

So ,

0.10 + A + 0.35 + B + C = 1

0.10 + 0.25 + 0.35 + B + C = 1

B + C  = 1 - 0.70

B + C  = 0.30  ......(i)

We have the expected value = 1.9

So, $\sum X P(X) = 19$     for x  = 0, 1, 2, 3, 4

⇒ (0 x 0.10) + (1 x 0.25) + (2 x 0.35) + (3 x B) + (4 x C) = 1.9

⇒ 0 + 0.25 + 0.70 + 3B + 4C = 1.9

⇒ 3B + 4C = 1.9 - 0.95

⇒ 3B + 4C = 0.95   ...................(ii)

From (i), we take the value of B = 0.30 - C and substitute it in the equation (i), we get,

⇒ 3( 0.30 - C) + 4C = 0.95

⇒ 0.90 - 3C + 4C = 0.95

⇒ C = 0.95 - 0.90

       = 0.05

Now substituting the value of C = 0.05 in (ii), we get,

⇒ B = 0.05 = 0.30

⇒ B = 0.25

c). The value of C is 0.05

             

4 0
4 years ago
If an injectable solution contains 25μg of a dug substance in each 0.5 mL, how many milliliters would be required to provide a p
Kay [80]

Answer:

5mL would be required to provide a patient with 0.25 mg of the drug substance.

Step-by-step explanation:

The problem states that an injectable solution contains 25μg of a dug substance in each 0.5 mL, and asks how many milliliters would be required to provide a patient with 0.25 mg of the drug substance.

So, the first step is the conversion of 25ug to mg, since the problem asks the answer in mg.

Each mg has 1000ug. So

1mg - 1000ug

xmg - 25ug

1000x = 25

x = \frac{25}{1000}

x = 0.025 mg

It means that each 0.5mL of the solution contains 0.025mg of the drug. How many milliliters would be required to provide a patient with 0.25 mg of the drug substance.

0.5mL - 0.025mg

xmL - 0.25mg

0.025x = 0.5*0.25

x = \frac{0.5*0.25}{0.025}

x = 10*0.5

x = 5mL

5mL would be required to provide a patient with 0.25 mg of the drug substance.

6 0
3 years ago
Mr. Roosevelt has 48 nails that each weigh 1.35 ounces. What is the weight of these nails in ounces?
zloy xaker [14]

Answer:

64.8 ounces

Step-by-step explanation:

48 x 1.35 = 64.8 ounces

5 0
3 years ago
Read 2 more answers
U Write 94 as a decimal.​
lions [1.4K]

Answer:0.94

Step-by-step explanation:

6 0
3 years ago
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