To solve the absolute value equation you first need to get everything not in the absolute value bars to the other side of the equation.
Step 1) Divide by 4
|n+8| = 14
*Remember: when solving absolute value equations, you make what the expression (n+8) is equal to negative and positive. Not the other way around.
Step 2) Make two equations
n+8 = 14
n+8 = -14
Solve and you'll see that n= 6 and -22
4.9÷7=0.7 because 49÷7=7, 4.9=49/10, and 7/10=0.7
the way I get the subsequent term, nevermind the exponents, the exponents part is easy, since one is decreasing and another is increasing, but the coefficient, to get it, what I usually do is.
multiply the current coefficient by the exponent of the first-term, and divide that by the exponent of the second-term + 1.
so if my current expanded term is say 7a³b⁴, to get the next coefficient, what I do is (7*3)/5 <----- notice, current coefficient times 3 divided by 4+1.
anyhow, with that out of the way, lemme proceed in this one.

so, following that to get the next coefficient, we get those equivalents as you see there for the 2nd and 3rd terms.
so then, we know that the expanded 2nd term is 24x therefore

we also know that the expanded 3rd term is 240x², therefore we can say that

but but but, we know what "n" equals to, recall above, so let's do some quick substitution
![\bf a^2n^2-a^2n=480\qquad \boxed{n=\cfrac{24}{a}}\qquad a^2\left( \cfrac{24}{a} \right)^2-a^2\left( \cfrac{24}{a} \right)=480 \\\\\\ a^2\cdot \cfrac{24^2}{a^2}-24a=480\implies 24^2-24a=480\implies 576-24a=480 \\\\\\ -24a=-96\implies a=\cfrac{-96}{-24}\implies \blacktriangleright a = 4\blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ n=\cfrac{24}{a}\implies n=\cfrac{24}{4}\implies \blacktriangleright n=6 \blacktriangleleft](https://tex.z-dn.net/?f=%5Cbf%20a%5E2n%5E2-a%5E2n%3D480%5Cqquad%20%5Cboxed%7Bn%3D%5Ccfrac%7B24%7D%7Ba%7D%7D%5Cqquad%20a%5E2%5Cleft%28%20%5Ccfrac%7B24%7D%7Ba%7D%20%5Cright%29%5E2-a%5E2%5Cleft%28%20%5Ccfrac%7B24%7D%7Ba%7D%20%5Cright%29%3D480%20%5C%5C%5C%5C%5C%5C%20a%5E2%5Ccdot%20%5Ccfrac%7B24%5E2%7D%7Ba%5E2%7D-24a%3D480%5Cimplies%2024%5E2-24a%3D480%5Cimplies%20576-24a%3D480%20%5C%5C%5C%5C%5C%5C%20-24a%3D-96%5Cimplies%20a%3D%5Ccfrac%7B-96%7D%7B-24%7D%5Cimplies%20%5Cblacktriangleright%20a%20%3D%204%5Cblacktriangleleft%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20n%3D%5Ccfrac%7B24%7D%7Ba%7D%5Cimplies%20n%3D%5Ccfrac%7B24%7D%7B4%7D%5Cimplies%20%5Cblacktriangleright%20n%3D6%20%5Cblacktriangleleft)
Answer:
see explanation
Step-by-step explanation:
Alternate exterior angles are congruent, thus
∠ RST = ∠ RQP , substitute values
7x + 11 = 4x + 32 ( subtract 4x from both sides )
3x + 11 = 32 ( subtract 11 from both sides )
3x = 21 ( divide both sides by 3 )
x = 7
Thus
∠ RST = 7(7) + 11 = 49 + 11 = 60°
∠ RQP = 4(7) + 32 = 28 + 32 = 60°