Which of these is a best practice for using graphics on a slide?

In a linux script, the line ____ is important because it identifies the file as a script.

igor_vitrenko [27]

The closest line to that would be the first line:

#!/bin/bash

echo "Hello World!"

BTW, the "#!" is referred to as a she-bang. When those are the first characters executed, the (requires an absolute path) program that follows is launched, and the rest of this file is given to it as data. To run this like a program, the execute permissions need to be set ( chmod 0755 script.sh ).

8 0

3 years ago

Need help ppplllleeeassse Hhheeelllppp

kondaur [170]

Answer:

Any curved surface of a 3d object..

5 0

4 years ago

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Evaluate the expression. Be sure to list a value of appropriate type (e.g., 7.0 rather than 7 for a double, Strings in quotes).

Mashutka [201]

<h2>Answer:</h2>

14.0

<h2>Explanation:</h2>

Using the level of precedence in Java,

From left to right;

(i) the first division operation will be done.

(ii)followed by the second division operation.

(iii)followed by the first multiplication operation.

(iv)followed by the third division operation.

(v)followed by the second multiplication operation.

(vi) followed by the first addition operation.

(vii)lastly followed by the second addition operation.

=================================================

Taking the steps above one after the other;

(i) the first division operation will be done (i.e 19 / 2)

=> Integer division in Java gives an integer result. Therefore, 19 / 2 = 9.5 will give 9.

So,

=> 19 / 2 / 2.0 + 2.5 * 6 / 2 + 0.5 * 4

=> 9 / 2.0 + 2.5 * 6 / 2 + 0.5 * 4

(ii)followed by the second division operation. (i.e 9 / 2.0)

=> From the result from step (i), the second division operation is now 9 / 2.0.

=> 9 / 2.0 = 4.5

So,

=> 9 / 2.0 + 2.5 * 6 / 2 + 0.5 * 4

=> 4.5 + 2.5 * 6 / 2 + 0.5 * 4

(iii)followed by the first multiplication operation. (i.e 2.5 * 6)

=> The first multiplication operation is given by 2.5 * 6

=> 2.5 * 6 = 15.0

So,

=> 4.5 + 2.5 * 6 / 2 + 0.5 * 4

=> 4.5 + 15.0 / 2 + 0.5 * 4

(iv)followed by the third division operation. (i.e 15.0 / 2)

=> The third division operation is given by 15.0 / 2

=> 15.0 / 2 = 7.5

So,

=> 4.5 + 15.0 / 2 + 0.5 * 4

=> 4.5 + 7.5 + 0.5 * 4

(v)followed by the second multiplication operation. (i.e 0.5 * 4)

=> The second multiplication operation is given by 0.5 * 4

=> 0.5 * 4 = 2.0

So,

=> 4.5 + 7.5 + 0.5 * 4

=> 4.5 + 7.5 + 2.0

(vi) followed by the first addition operation. (i.e 4.5 + 7.5)

=> The first addition operation is given by 4.5 + 7.5

=> 4.5 + 7.5 = 12.0

So,

=> 4.5 + 7.5 + 2.0

=> 12.0 + 2.0

(vii) lastly followed by the second addition operation. (i.e 12.0 + 2.0)

=> The second addition operation is given by 12.0 + 2.0

=> 12.0 + 2.0 = 14.0

So,

=> 12.0 + 2.0

=> 14.0

Therefore, 19 / 2 / 2.0 + 2.5 * 6 / 2 + 0.5 * 4 = 14.0

In Java, the order of precedence for arithmetic operators is;

=> /, * and %

=> followed by + and -

6 0

3 years ago

Some projectors use a connection technology called _______________ that enables long-range connectivity for uncompressed HD vide

Rzqust [24]

Answer:

HDbaseT

Explanation:

HDbaseT is a global connectivity standard for transmitting uncompressed high definition videos, audios, power, usb, ethernet home networking and some control signals for up to 100 meters, over a category cable like Cat 5a or Cat 6 cables.

The projector uses the HDbaseT for these reasons and for the fact that it eliminates clusters in cables without affecting its performance or high quality. This gives a high quality output display from the projector.

5 0

3 years ago

Write a method that takes three numerical String values and sums their values.

Sphinxa [80]

Answer:

Algorithm:

Take a int variable c=0.
Run the loop from 0 to String length.
Get the each index value using charAt() method which will return the char value.
Convert that char into int by typecasting or any other way.
Now check that ASCII fall into the range of 48-57 for 0-9 int number.
If it matches then first convert that number into integer using Integer.parseInt().
Then add with the c and store to the same variable i.e c.
Repeat from 3-7 till the end of the loop.
At the end of loop , Print c outside the loop.

Explanation:

// Java program to calculate sum of all numbers present

// in a string containing alphanumeric characters

class GFG

{

// Function to calculate sum of all numbers present

// in a string containing alphanumeric characters

static int findSum(String str)

{

// A temporary string

String temp = "";

// holds sum of all numbers present in the string

int sum = 0;

// read each character in input string

for(int i = 0; i < str.length(); i++)

{

char ch = str.charAt(i);

// if current character is a digit

if (Character.isDigit(ch))

temp += ch;

// if current character is an alphabet

else

{

// increment sum by number found earlier

// (if any)

sum += Integer.parseInt(temp);

// reset temporary string to empty

temp = "0";

}

// atoi(temp.c_str()) takes care of trailing

// numbers

return sum + Integer.parseInt(temp);

}

// Driver code

public static void main (String[] args)

{

// input alphanumeric string

String str = "1abc5yz7";

System.out.println(findSum(str));

}

4 0

3 years ago

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