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Vilka [71]
3 years ago
9

Determine the concentration of an aqueous solution that has an osmotic pressure of 3.9 atm at 37°C if the solute is sodium chlor

ide. Assume no ion pairing.
Chemistry
1 answer:
Snowcat [4.5K]3 years ago
8 0

Answer:

Concentration for the solution is 0.153 mol/L

Explanation:

Formula for the osmotic pressure is  π = M . R . T . i

where M is molarity (concentration), R the universal constant for gases and T is Absolute T° (T°C + 273)

π = Osmotic pressure.

Let's replace the data given:

3.9 atm =  M . 0.082L.atm/mol.K . 310K

3.9 atm / 0.082 mol.K/L.atm . 310K = 0.153 mol/L (M)

i = Van't Hoff factor (ions from the solute dissolved in solution)

In this case, we assumed no ion pairing, so i = 1

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That's the basics of both the H-H bond and all the other diatomic bonds as well. 
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3 years ago
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Ilia_Sergeevich [38]

Answer:

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3 years ago
If the dimensions of a cube-shaped cell with a volume of 1 pm were to
melamori03 [73]

Answer:

B

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A cube shaped cell with a 1 um³ volume would have a dimensions of 1 x 1 x 1   (because volume = length x width x height and 1 x 1 x 1 =1)

If we double the dimensions, we have a cube with the dimensions 2 x 2 x 2.

The surface area of each face of the cube is the length x width, so 2 x 2. This means the surface area of each face of the cube is 4 um².

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3 years ago
What is the age of mummified primate skin that contains 8.25% of the original quantity of 14C?
rjkz [21]

Answer:

20619.4793 years

Explanation:

The half life of carbon-14 = 5730 years

The formula for the half life for a first order kinetic reaction is:

t_{1/2}=\frac {ln\ 2}{k}

Where,  

t_{1/2} is the half life

k is the rate constant.

Thus rate constant is:

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k = 1.21×10⁻⁴ years ⁻¹

Using integrated rate law as:

ln\ \frac {A_t}{A_0}=-k\times t

Where,

A_t is the concentration at time t

A_0 is the initial concentration

Given that the final concentration contains 8.25 % of the original quantity which means that:

\frac {A_t}{A_0}=0.0825

So,

ln(.0825)= -1.21×10⁻⁴×t

<u> t = 20619.4793 years</u>

<u></u>

8 0
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Nona= 9, hepta= 7, hexa= 6, tetra= 4
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