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Vilka [71]
3 years ago
9

Determine the concentration of an aqueous solution that has an osmotic pressure of 3.9 atm at 37°C if the solute is sodium chlor

ide. Assume no ion pairing.
Chemistry
1 answer:
Snowcat [4.5K]3 years ago
8 0

Answer:

Concentration for the solution is 0.153 mol/L

Explanation:

Formula for the osmotic pressure is  π = M . R . T . i

where M is molarity (concentration), R the universal constant for gases and T is Absolute T° (T°C + 273)

π = Osmotic pressure.

Let's replace the data given:

3.9 atm =  M . 0.082L.atm/mol.K . 310K

3.9 atm / 0.082 mol.K/L.atm . 310K = 0.153 mol/L (M)

i = Van't Hoff factor (ions from the solute dissolved in solution)

In this case, we assumed no ion pairing, so i = 1

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Answer:

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How many grams of sodium chloride could be produced from 41.3 L of chlorine gas?
babymother [125]

Answer:

The grams of sodium chloride that will be made is 292.5 g. calculation. 2Na + Cl₂ → 2NaCl. step 1: calculate the moles of Na. moles = mass/molar mass. From periodic table the molar mass of Na = 23 g/mol. moles = 115 g/23 g / mol = 5 moles. Step 2 : use the mole ratio to determine the moles of NaCl. Na:NaCl is 2:2 = 1:1 therefore the moles of NaCl is also = 5 moles.

Explanation:

We know sodium is a very active metal and chlorine is also a very reactive non-metal. Usually, metals like to eliminate electrons and non-metals such as halogens like to accept electrons. Sodium readily eliminate its last shell electrons become Na+ cation and chlorine accepts that electron to form Cl-anion.

6 0
2 years ago
A certain reaction has an activation energy of 66.41 kJ/mol. At what Kelvin temperature will the reaction proceed 3.00 times fas
swat32

Answer : The temperature will be, 392.462 K

Explanation :

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant at T_1  = K_1

K_2 = rate constant at T_2 = 3K_1

Ea = activation energy for the reaction = 66.41 kJ/mole = 66410 J/mole

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 293 K

T_2 = final temperature = ?

Now put all the given values in this formula, we get:

\log (\frac{3K_1}{K_1})=\frac{66410J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{293K}-\frac{1}{T_2}]

T_2=392.462K

Therefore, the temperature will be, 392.462 K

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3 years ago
How did the color of the foxes’ environment change? Explain what happened to the foxes over many generations.
xxMikexx [17]

Answer:

The answer is below

Explanation:

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