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Ahat [919]
2 years ago
12

If i walk 2 block in 15 minutes what will my speed be?

Mathematics
2 answers:
Liula [17]2 years ago
7 0

Answer:

That means you walked 1 block in 7.5 minutes

Step-by-step explanation:

Divide 15/2 and that gives 7.5.

We can not find the speed unless if we are given the distance of the blocks but we can find the unit rate....

Art [367]2 years ago
3 0

Answer:

Your answer would be 6mph.

Step-by-step explanation:

Calculate your running or walking speed, distance, or time with Verywell's ... You may also need to know your pace when registering for an event or race such as a ... A pace may not be a round number of minutes, in which case you will need to ... Running 6 miles in 1 hour: 6 / 1 = 6 miles per hour (mph);

(Got it from google)

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An investment of 100,000 AED increases at a rate of 16% per year. What is
stepan [7]

Answer:

1,946,075.95 AED

Step-by-step explanation:

Firstly, we write the general formula for an exponential increase as follows;

V(t) = A( 1 + r)^t

where V(t) is the value after some number of years t

A is the investment amount which is 100,000 AED

r is the rate of increase which is 16% = 16/100 = 0.16

t is the number of years which is 20

substituting these values;

V(20) = 100,000( 1 + 0.16)^20

V(20) = 100,000(1.16)^20

V(20) = 1,946,075.95 AED

7 0
2 years ago
If a cross section of the paperweight is cut parallel to the base, which shape describes the cross section?
ryzh [129]

Answer:

Yes, that's right:  the cross section will be a rectangle (but also a parallelogram).

Step-by-step explanation:

3 0
3 years ago
Linda scored 3 points more than twice Lisa's points on a driver's ed test. Lisa scored p points.
Flura [38]
Ok so what I would do Is I would do 3 x p=m 
3 0
2 years ago
Find the HCF of 27, 63, 54 using prime factorization method.
Step2247 [10]

Answer:

27 = 3 , 3, 3

63= 3 , 3, 7

54= 3 , 3, 3, 2

HCF OF 27, 63 AND 54 = 3 X 3 = 9

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7 0
2 years ago
Algebra help
Vilka [71]
To determine the correct ordered pairs which will agree with the function, we can substitute values to the function and see whether it agree with each other. We do as follows:

<span>(0,1)
</span><span> f(x)=128(0.5)^0
</span><span> f(x)=128
</span><span>
(1,64)
</span><span> f(x)=128(0.5)^1
</span>f(x) = 64  <--------CORRECT ANSWER<span>

(3,16)
</span><span> f(x)=128(0.5)^3
f(x) = 16 <--------CORRECT ANSWER
</span><span>
(8,0.5)
</span><span> f(x)=128(0.5)^8
f(x) = 1/2

Hope this answers the question. Have a nice day.</span>
5 0
3 years ago
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