Answer:
D
21√2/2
C
C
C
Step-by-step explanation:
For all problems, the ratios of the lengths of the sides are:
30-60-90 triangle 1 : √3 : 2
45-45-90 triangle 1 : √2 : √2
Problem 3:
30-60-90 triangle at left
Hypotenuse = 11
Short leg = 11/2
Long leg = 11/2 × √3
45-45-90 triangle at right
x = 11/2 × √3 × √2 = 11√6/2
Answer: D
Problem 4:
30-60-90 triangle at top
Hypotenuse = 7√3
Short leg = 7√3/2
Long leg = 7√3/2 × √3 = 7 × 3/2 = 21/2
45-45-90 triangle at right
x = 21/2 × √2 = 21√2/2
Answer: 21√2/2
Problem 7:
30-60-90 triangle
Long leg = 4√3
Short leg = y = 4√2/2 = 2√2
Answer: C.
Problem 6:
30-60-90 triangle at left
Hypotenuse = 12√6
Short leg = 12√6/2 = 6√6
Long leg = 6√6 × √3 = 6√2√3√3 = 18√2
45-45-90 triangle at right
x = 18√2/√2 = 18
Answer: C.
Problem 8:
45-45-90 triangle
Hypotenuse = 2
Leg = y = 2/√2 = 2√2/(√2√2) = √2
Answer: C.
he tuition of $3,200 increased by 5% is: 3,200 + 0.05*3,200 = 1.05*3,200 = $3,360
Elizabeth saved equal amounts each month for 12 months the previous year thus we divide $3,360 by 12 to find how much she saved monthly:
$3,360 : 12 = $280
The minimum amount Elizabeth should have saved monthly is $280.
Answer:
19 students per teacher and 10 students per tutor
Step-by-step explanation:
To find the amount of students per teacher and per tutor you have to divide
95 students /5 teachers
19 students per teacher
40 students /4 tutors
10 studetns pet tutor
Answer:
if it is just the 10+36-6 then that is 40 but then if it is 2/5 10+36-6 then that would be 16
Step-by-step explanation:
add 10 and 36 which is 46 then subtract 6 which is 40 then get the 2/5 which would be 16 hope this helps you
