Answer:
Third option: 12x^2+8x+25
Step-by-step explanation:
s1=8x^2
s2=4x^2+15
s3=8x+10
Total perimeter of the pool edge: P
P=s1+s2+s3
Replacing s1, s2 and s3 in the formula above:
P=(8x^2)+(4x^2+15)+(8x+10)
P=8x^2+4x^2+15+8x+10
Adding like terms:
P=12x^2+8x+25
It’s written as 0.6 in decimal form
The answer I'm pretty sure is B but I can't really explain it, sorry
Answer:
- 2(L +W) ≤ 600
- W ≤ 200
- L ≥ 2W
Step-by-step explanation:
We assume the problem wording means the length is to be at least 2 times <em>as long as</em> the width. (<em>Longer than</em> usually refers to a difference, not a scale factor.)
If we let "W" and "L" represent the width and length, respectively, then we can translate the problem statement to ...
2(L + W) ≤ 600 . . . . . . the perimeter is twice the sum of length and width
W ≤ 200 . . . . . . . . . . . . the width is at most 200 inches
L ≥ 2W . . . . . . . . . . . . . the length is at least twice the width
14/33 or in decimal form is 0.4242
