The distance between the two points is 5.4
Explanation:
The points are (-1,-9) and (1,-4)
The distance between the two points can be determined using the formula
Substituting the values in the formula, we get,
Adding the values,
Squaring the terms, we get,
Simplifying, we have,
Thus, the distance between the two points is 5.4
<em>Answer:</em>
<em>For grade A ,a student needs Z score of 2 or above, the required score is</em>
<em> X = 68 + 12Z =92, For grade B, a student needs Z score between 1 and 2 . </em>
<em> The required score is = 68 + (12 * 1) < X = 68 + ( 12 * 2) = 80 < X < 92, For grade C ,a student needs Z score between -1 and 1 . The required score is = 68 + ( 12 * x - 1) < X = 68 + (12 * x 1) = 56 <X<80. For the grade D, a student needs Z score between -2 and -1 . </em>
<em> The required score is = 68 + (12 * x -2) < X = 68 + (12 * x -1) = 44< X< 56</em>
Step-by-step explanation:
<em>From the given question, </em>
<em>let the rv X represent student's score.</em>
<em>Z = x - 68/12 ~ N (0,1 )</em>
<em>Now, we know for a standard normal distribution</em>
<em>Thus,</em>
<em>For grade A ,a student needs Z score of 2 or above, the required score is</em>
<em> X = 68 + 12Z =92</em>
<em>For grade B, a student needs Z score between 1 and 2 . </em>
<em> The required score is = 68 + (12 * 1) < X = 68 + ( 12 * 2) = 80 < X < 92</em>
<em>For grade C ,a student needs Z score between -1 and 1 . </em>
<em> The required score is = 68 + ( 12 * x - 1) < X = 68 + (12 * x 1) = 56 <X<80</em>
<em>For the grade D, a student needs Z score between -2 and -1 . </em>
<em> The required score is = 68 + (12 * x -2) < X = 68 + (12 * x -1) = 44< X< 56</em>
<em>For student with score less 44 gets an F.</em>
<em>Note: find an attached image for the graphic sketch of the normal distribution.</em>
