3 years ago

Please help me!! You must be good in math.

1 answer:

8 0

It is SAS because
1) it is given that sides are equal (AB=CD)
2)it is also given that angles B and C are equal
3) BC is a common side so it is equal in both triangles.

answer: SAS

You might be interested in

14+-6 what is the answer answer

Irina-Kira [14]

Answer:

the answer is 8. just think of it as subtraction. subtract +6 from +14. then you get the answer for +14+-6.

3 0

3 years ago

How would i solve 15=x+7

lakkis [162]

Answer:

15-7=8

Step-by-step explanation:

you will have to use inverse operation

8 0

2 years ago

Read 2 more answers

Does anyone know what is 1/2⋅17.?

Free_Kalibri [48]

Answer:

8.5

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Can someone please help me on this question.

lesya692 [45]

Answer:

Step-by-step explanation:

$3x^{2} + 5x-12=0$

$-12=-5x-3x^{2}$

$(-12=-5x-3x^{2} ) * -1$

$\sqrt{12=5x+3x^{2}$

4 0

2 years ago

A quantity of gas has a volume of 0.20 cubic meter and an absolute temperature of 333 degrees kelvin. When the temperature of th

mezya [45]

$\displaystyle \\ 
\texttt{Notations: } \\ 
P = \texttt{pressure} \\ 
V = \texttt{volume} \\ 
T = \texttt{absolute temperature} \\ \\ 
\texttt{We use the formula: }~ \frac{P \times V}{T} = \texttt{constant} \\ \\ 
\frac{P_1 \times V_1}{T_1} = \frac{P_2 \times V_2}{T_2} \\ \\ 
P_1 = P_2 \\ \\ 
\Longrightarrow~~\frac{V_1}{T_1} = \frac{V_2}{T_2}\\\\ 
\Longrightarrow~V_2 =\frac{V_1 \times T_2}{T_1}= \frac{0.2~m^3 \times 533^oK}{333^oK}=\frac{106.6}{333}= 0.3(201)\approx \boxed{0,32~m^3}$

8 0

3 years ago