They’re all -4 ,, what exactly are you asking ?
9514 1404 393
Answer:
- square: 12 ft sides
- octagon: 6 ft sides
Step-by-step explanation:
This problem can be worked in your head.
If the perimeters of the square and regular octagon are the same, the side length of the 4-sided square must be the same as the length of 2 sides of the 8-sided octagon. Since the side of the square is 6 ft more than the side of the octagon, each side of the octagon must be 6 ft, and each side of the square must be 12 ft.
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We can let s represent the side length of the octagon. Then we have ...
8s = perimeter of octagon
4(s +6) = perimeter of square
These are equal, so ...
4(s +6) = 8s
s +6 = 2s . . . . . . divide by 4
6 = s . . . . . . . . . . subtract s
The octagon has 6-ft sides; the square has 12-ft sides.
Answer:
MOP=33
Step-by-step explanation:
MOP + MON = NOP
Substitute what we know
MOP = 3x-3
MON = 4x+9
NOP = 90 right angle
3x-3+4x+9 = 90
Combine like terms
7x+6 =90
Subtract 6 from each side
7x+6-6=90-6
7x = 84
Divide each side by 7
7x/7 = 84/7
x =12
We need to find MOP
MOP = 3x-3
=3(12)-3
36-3
33
Answer:
x = 27
y = 29
Step-by-step explanation:
