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lianna [129]
2 years ago
12

38. Nate and Gavin are playing a video game. Gavin has scored eleven more than twice the number of

Mathematics
1 answer:
larisa [96]2 years ago
3 0
Gavin scored 465 points
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Describe how the graph of y= x – 12 is like the graph of y= x and how it is different
puteri [66]
The two graphs have the same slope.  But the graph of <span>y= x – 12 is 12 units below the graph of y = x.  We call that a "vertical translation."

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6 0
3 years ago
Out of 200 people eating at a diner, 70% ordered
scZoUnD [109]

Answer:

140 people

Step-by-step explanation:

4 0
2 years ago
HELP I WILL GIVE 5 POINTS TO WHOM EVER CAN ANSWER THESE LAST 2 QUESTIONS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
vodka [1.7K]
Group and factor
undistribute then undistribute again
remember
ab+ac=a(b+c)
this is important



6d^4+4d^3-6d^2-4d
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2d(3d^3+2d^2-3d-2)
group insides
2d[(3d^3+2d^2)+(-3d-2)]
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factor that difference of  2 perfect squares
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77.
group
(45z^3+20z^2)+(9z+4)
factor
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7 0
3 years ago
Se vendieron un total de 430 boletos para la obra de teatro escolar. Los boletos eran o de adulto o de estudiante. Se vendieron
BartSMP [9]

Resolviendo un sistema de ecuaciones, veremos que se vendieron 250 boletos de adulto.

<h3>¿Cuántos boletos de adulto fueron vendidos?</h3>

Definamos las variables:

  • x = boletos de adulto vendidos.
  • y = boletos de estudiantes vendidos.

Se vendieron un total de 430 boletos, entonces:

x + y = 430

Y se vendieron 70 boletos de estudiante menos que boletos de adulto:

y = x - 70

Tenemos el sistema de ecuaciones:

x + y = 430

y = x - 70

Para resolverlo, podemos reemplazar la segunda ecuación en la primera:

x + y = 430

x + (x - 70) = 430

2x = 430 + 70 = 500

x = 500/2 = 250

Se vendieron 250 boletos de adulto.

Sí quieres aprender más sobre sistemas de ecuaciones:

brainly.com/question/13729904

#SPJ1

5 0
2 years ago
When n=343 college students are randomly selected and surveyed, it is found that x=110 own a car. Find a 99% confidence interval
Liono4ka [1.6K]

Answer:

The margin of error will be "0.65". A further explanation is provided below.

Step-by-step explanation:

The given values are:

n = 343

x = 110

At 99% confidence level,

\alpha = 1-99%

  =1-0.99

  =0.01

then,

\frac{\alpha}{2} =\frac{0.01}{2}

  =0.005

or,

Z_{\frac{\alpha}{2} }=Z_{0.005}

     =2.576

Now,

The point estimate will be:

⇒  \hat{P}=\frac{x}{n}

⇒      =\frac{110}{343}

⇒      =0.321

or,

⇒  1-\hat{P}=1-0.321

⇒            =0.679

The margin of error will be:

⇒  E=Z_{\frac{\alpha}{2} }\times \sqrt (\frac{(\hat{P}\times (1 - \hat{P})) }{n} )

On substituting the above values, we get

⇒      =2.576\times \sqrt{\frac{0.321\times 0.679}{343} }

⇒      =2.576\times \sqrt{\frac{0.217959}{343} }

⇒      =0.065

hence,

⇒  \hat{P}-E

⇒  0.321-0.065

⇒  0.256,0.386

6 0
3 years ago
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