The probability of it happening once is 1/5, since 10/50 simplifies to 1/5. Because the ticket goes back in the bag, the probability stays constant at 1/5.
For it to happen twice, you multiply the probability of it happening once, twice.
1/5 • 1/5 = 1/25 probability of it being Gary's name twice in a row.
Answer:
<h3>Part A</h3>
The graph is non-linear as it is not a continuous straight line (with only one slope).
<h3>Part B</h3>
<u>Increasing</u>: the y-value increases as the x-value increases
<u>Constant</u>: the y-value stays the same as the x-value changes
<u>Decreasing</u>: the y-value decreases as the x-value increases
Therefore,
- Increasing segment: Between 0 and 2 seconds
- Constant segment: Between 2 and 3 seconds
- Decreasing segment: Between 3 and 5 seconds
<h3>Part C</h3>
For the first 2 seconds, the ant moves 6 cm from a hole in the tree at a steady speed of 3 cm per second. For the next second, the ant is at rest then turns around. For the next 2 seconds, the ant moves 6 cm back to the hole at a steady speed of 3 cm per second. The ant then stops.
2^2a^2+b^2
4a^2+b^2
not sure if this is correct but here ya go
To get the constant of proportionality (unit rate) you must find the miles driven in 1 hour. To get this you simply divide 200 by 4...
200÷4=50
So, the constant of proportionality is 50 mph.
Given :
Factory has supplies expenses of $1135.78 a day.
Company earns $60,128.72 in one week.
To Find :
The factory's total profit or loss in one week.
Solution :
Expenses of factory of a week :
E =$( 1135.78 × 7 ) = $7950.46 .
Now, profit is given by :
P = $60,128.72 - $7950.46
P = $52178.26
Therefore, total profit of factory in one week is $52178.26 .
Hence, this is the required solution.