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3 years ago

What is the perimeter of a square if one of the sides is three mi?

2 answers:

7 0

12 m. 3 + 3 + 3 + 3. A square is the one in which all sides are equivalent, so if one side is 3, then the other 3 must be 3, which is 3 + 3 + 3 + 3

Norma-Jean [14]3 years ago

3 0

3+3+3+3=12.Because it is a square....A square has all sides the same so we just add 3 +3+3+3.

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Help me asap .no links! imma fail please help

Dovator [93]

Bear with my working out lol,

8x3 = 24in^2
9x12 = 108in^2
6x7 = 42in^2
(11x4) / 2 = 22in^2

Total = 196in^2

Try that, I couldn’t tell where the tip on the triangle fell at. So it could be wrong but that is what I got and what I would put :)

4 0

2 years ago

Read 2 more answers

The product of seven and the difference between a number and ten

Rina8888 [55]

Answer:

7(x-10)

Step-by-step explanation:

7×(x-10)

you ×7by whatever x-10 is

6 0

3 years ago

Read 2 more answers

Find all the powers of 4 in the range 4 through 1000

marissa [1.9K]

Powers of 4 are like 4^1, 4^2, 4^3 and so on
remember that 4^x means 4 times itself x times for example
4^3=4 times iteslef 3 times=4 times 4 times 4

so the multipules of the powers of 4 are just 4 times of the previous
so we will list

4^1=4
4^2=16
4^3=64
4^4=256
4^5=1024

1024 is already more than 1000 so the list stops and is
1,16,64,256

8 0

3 years ago

Which equation, when solved results in a different value of x than the other three?

Talja [164]

Answer:

$-\frac{7}{8}(-\frac{8}{7})x-\frac{3}{4}=20(-\frac{8}{7})$

Step-by-step explanation:

The complete question in the attached figure

Verify each case

Part 1) we have

$-\frac{7}{8}x-\frac{3}{4}=20$

solve for x

$\frac{7}{8}x=-\frac{3}{4}-20$

$\frac{7}{8}x=-\frac{83}{4}$

$x=-\frac{83}{4}(\frac{8}{7})$

$x=-\frac{166}{7}$

Part 2) we have

$\frac{3}{4}+\frac{7}{8}x=-20$

Multiply both sides by -1 and rearrange the terms on the left side to get

$-\frac{7}{8}x-\frac{3}{4}=20$

This expression is the same that the expression in Part 1)

That means, that the equations Part 1) and Part 2) are equivalent

therefore

$x=-\frac{166}{7}$

Part 3) we have

$-7(\frac{1}{8})x-\frac{3}{4}=20$

Remember that

$-7(\frac{1}{8})x=-\frac{7}{8}x$

This expression is the same that the expression in Part 1)

That means, that the equations Part 1) and Part 3) are equivalent

therefore

$x=-\frac{166}{7}$

Part 4) we have

$-\frac{7}{8}(-\frac{8}{7})x-\frac{3}{4}=20(-\frac{8}{7})$

This equation is not equivalent to the other three, because some terms are multiplied by -8/7 and others are not. When different things are done on either side of the equal sign, it changes the equation, resulting in a different solution

6 0

3 years ago

PLEASE HELP

andreyandreev [35.5K]

Answer:

the answer is 30

Step-by-step explanation:

Hope that helps you :)

6 0

3 years ago