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tester [92]
3 years ago
15

Who can friend me first also view my profile

Mathematics
1 answer:
gavmur [86]3 years ago
6 0

Answer:

LOL OK

Step-by-step explanation:

HAHAHAHAHAHAHAHAHAHAHAHA

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The population of algae in an experiment has been increasing by 5% each day. If there were 5p algae at the beginning of the expe
Ostrovityanka [42]

Answer:

Number of algae in 7 days = 70.355

Step-by-step explanation:

Given:

Algae in beginning = 50

Rate of increasing = 5% per day = 0.05

Number of days = 7 days

Find:

Number of algae in 7 days.

Computation:

Number\ of\ algae\ in\ 7\ days = Algae\ in\ beginning(1+Rate\ of\ increasing)^{Number\ of\ days}\\\\Number\ of\ algae\ in\ 7\ days = 50(1+0.05)^7\\\\Number\ of\ algae\ in\ 7\ days = 70.355

Number of algae in 7 days = 70.355

4 0
3 years ago
What is the slope of the line that passes through (2,6) and (6,9)
Alenkasestr [34]

Answer:

3,3

Step-by-step explanation:

6 0
3 years ago
Plllllplzzzzzzzzzzzzzzzzzzzzzzzzzz
Natalija [7]

Hello there!

The answer would be C since we are looking to find how far she ran based on the amount of miles that has passed.

As stated above, 6 minutes. However to find out how far she runs we have to change the speed to miles per minute.

6 minutes per mile is equal to 1/6 of a mile per minute

Formula for Distance is speed x time

The distance is d, the time is t and the speed is 1/6.

Plug it in:

d = 1/6t

Lastly, multiply by 6 on both sides.

d x 6 = 1/6t x 6

1/6 x 6 = 1t

6d = 1t

Answer: t= 6d

5 0
3 years ago
A water tank is being filled with water. Before water is pumped in, the water level in the tank is 11 inches high. After 20 minu
serg [7]

Answer:

(58-11) divided by 20

Step-by-step explanation:

6 0
3 years ago
According to the University of Nevada Center for Logistics Management, 6% of all mer-
Fudgin [204]

Answer:

a) The point estimate of the proportion of items returned for the population of

sales transactions at the Houston store = 12/80 = 0.15

b) The 95% confidence interval for the proportion of returns at the Houston store = [0.0718 < p < 0.2282].

c) Yes.

We set an hypothesis and construct a test statistics. The test statistics result gives us:

Z calculated  = 2.2545, and this gives us the p-value = 0.0121. We assumed 95% confident interval. Hence, the level of significance (α) = 5%. Conclusively, since the p-value ==> 0.0121 is less than (α) = 5%, the test is significant. Hence, the proportion of returns at the Houston store is significantly different from the returns  for the nation as a whole.

Step-by-step explanation:

a) Point estimate of the proportion = number of returned items/ total items sold = 12/80 = 0.15.

b) By formula of confident interval:

CI(95%) = p ± Z*\sqrt{\frac{p*(1-p)}{n} }  =  0.15 \pm 1.96 *\sqrt{\frac{0.15*(1-0.15)}{80} },

CI(95%) = [0.0718 < p < 0.2282]

c) The hypothesis:

H_{0}: The proportion of returns at the Houston store is not significantly different from the returns  for the nation as a whole.

H_{a}: The proportion of returns at the Houston store is significantly different from the returns  for the nation as a whole.

The test statistics:

Z = \frac{\hat{p} - p_{0}}{\sqrt{\frac{p*(1-p)}{n} }}, where p_{0} is the proportion of nation returns.

Z calculated  = 2.2545, and this gives us the p-value = 0.0121. We assumed 95% confident interval. Hence, the level of significance (α) = 5%. Conclusively, since the p-value ==> 0.0121 is less than (α) = 5%, the test is significant. Hence, the proportion of returns at the Houston store is significantly different from the returns  for the nation as a whole.

6 0
3 years ago
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