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aleksley [76]
3 years ago
5

How do you solve b^2=-3b

Mathematics
2 answers:
Andrej [43]3 years ago
6 0

Answer:

b=0,-3

Step-by-step explanation:

b^2+3b=0

b(b+3)=0

b=0

b+3=0

b=-3

tamaranim1 [39]3 years ago
5 0

Answer:

b = 0 OR b = -3

Step-by-step explanation:

To start off with, we know that this must be a quadratic equation because there's a "^2".

Firstly, we have to bring everything over to one side of the equation. This means we have to add 3b to both sides, as we want the right-hand side to be 0.

b^2 = -3b

+3b   +3b

b^2 + 3b = 0

Secondly, we have to factorise. We need to see what number goes into both "b^2" AND "3b".

That is "b".

b^2 + 3b = 0

factor out b

b(b + 3) = 0

Thirdly, we have to use the Null Factor Law to find out what b equals. The Null  Factor Law states that if an equation equals 0, then one of the terms must either be 0, or the negative of the other number.

Hence, there are two answers.

b = 0

OR

b = -3

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1
Tcecarenko [31]

Answer:

It is not possible for the student to receive an A grade in the class.

It is possible for the student to receive a B grade in the class.

Step-by-step explanation:

We are given that in the DBE 122 class, there are 350 possible points. These points come from 5 homework sets that are worth 10 points each and 3 exams that are worth 100 points each.

A student has received homework scores of 7, 8, 7, 5, and 8, and the first two exam scores are 81 and 80.

Firstly, we will calculate how many points have been scored by the student.

Number of possible points = 350

The points scored by the student in homework = 7 + 8 + 7 + 5 + 8 = 35 points.

The scores of the student on the two exams = 81 + 80 = 161 points

So, the total points scored by the students = 35 + 161 = 196 points.

As it is given in the question that if the grade percentage is 0.9 or higher then the student will get an A, i.e;

If the total possible points are 350 points; 90\% \text{ of } 350 = \frac{90}{100}\times 350 = 315 \text{ points}

This means that the student must have to score 315 points to get an A grade.

Till the second exam, the total points scored by the students are 196 points. If the student scored full 100 marks in the third exam, then the total points scored by the student will be = 196 + 100 = 296 points.

Since 296 < 315, this means that it is not possible for the student to receive an A in the class.

Also, it is given in the question that if the grade percentage is between 0.8 and 0.9 the student will get a B, i.e, the student must obtain a minimum of 80% to get B grade.

If the total possible points are 350 points; 80\% \text{ of } 350 = \frac{80}{100}\times 350 = 280 \text{ points}

This means that the student must have to score a minimum of 280 points to get a B grade.

Till the second exam, the total points scored by the students are 196 points. If the student scored full 100 marks in the third exam, then the total points scored by the student will be = 196 + 100 = 296 points.

Since 296 > 280, this means that it is possible for the student to receive a B grade in the class.

3 0
3 years ago
A box of chocolates contains five milk chocolates, three dark chocolates, and 8 white chocolates. You randomly select and eat th
Nitella [24]

Answer: no clue

Step-by-step explanation

5 0
4 years ago
Please help i dont get this at all so please i will highly appreciate it .Thank youuu!!!
Montano1993 [528]

Answer:

4y^4

Step-by-step explanation:

This polynomial is supposed to be ordered:

-3x^4+4y^4+5x^2y^2-10xy^3+9x^3y

I dont totally understand the question but I hope the ordered polynomial helps

6 0
2 years ago
To estimate the proportion of brand-name lightbulbs that are defective, a simple random sample of 400 brand-name lightbulbs is t
yaroslaw [1]

Answer:

X is a binomial random variable

Then the condition is met

Step-by-step explanation:

Sample size   n₁  = 400

X represents the number of brand-name lightbulbs)

P(X) = 44/400

P(X) = 0,11

X  is a binomial random variable it only could be either no defective or defective ( only two conditions or values).

To make use of the condition of approximation of binomial distribution to a normal distribution it is required that the products:

p*n  =  0,11*400  =  44      and    q  =  1  - 0,11   q =  0,89

q*n  =  0,89 * 400  =  356

both  p*n  q*n  are greater than 5.

Then the condition is met

4 0
3 years ago
The measure of angle one is five less than four times the measure of angle 2. if angle 1 and angle 2 from a linear pair, what ar
Montano1993 [528]
Linear pairs add up to 180 degrees.

x=4y-5
x+y=180

Substitute x
4y-5+y=180
5y-5=180
5y=185
y=37

Plug the y value in
x+37=180
x=143

Final answer: angle 1= 143 degrees, angle 2= 37 degrees
6 0
3 years ago
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