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ss7ja [257]
3 years ago
11

How many five-digit numbers can be created using the digits 0-9?

Mathematics
1 answer:
mash [69]3 years ago
4 0
The true answer is 90,000 but 100,000 is the closest
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Solve the following inequality.<br><br> IMAGE ATTACHED
kotykmax [81]
The answer is D.

First, separate the compound equality into 2
1st -3 (x-4) greater than/ equal to 21
2nd -3( x-4) < 30

Second, solve the inequality for x
1st x less than/ equal to -3
2nd x > -6

Third, find the intersection
D. -6 < x (less than/equal) to -3

I hope this helped, and if you don’t mind, giving me brainiest!

6 0
3 years ago
Find the equation of the line through point (1,5) and perpendicular to +3=6 x (e.g. 1/2 for 12
vovangra [49]

Answer:

YFHKIMEDAIOUKIMENAUODIOOSHIETIAOKURETAAAAA

Step-by-step explanation:

7 0
3 years ago
What does this mean ----&gt;&gt; 9e+10 please explain the answer
GenaCL600 [577]
This expression can't be solved because we don't know the value of e. Basically what this means is that e, an unknown number, is first being multiplied by 9, and it is then added by 10. You will just leave it as it is.
5 0
3 years ago
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t
xz_007 [3.2K]

Full Question

A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.

Determine the spring constant k.

Answer:

Spring Constant = 1000Nm^-1

Step-by-step explanation:

Given

Mass = 10kg

Spring Extension = 9.8cm

Spring Constant K = Force/Extension

Force = Mass * Acceleration

Force = 10 * 9.8 = 9.8N

Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m

Spring constant = 98 / 0.098

Spring Constant = 1000Nm^-1

3 0
3 years ago
Please Help!!
algol13
When you see questions of this nature, test the individual inequalities and look out for their intersection.

For
y < \frac{2}{3} x
Choose a point in the lower or upper half plane created by the line
y = \frac{2}{3} x
The above line is the one which goes through the origin.

Now testing (1,0) yields,

0 < \frac{2}{3} (1)
That is,

0 < \frac{2}{3}
This statement is true. So we shade the lower half of
y = \frac{2}{3} x

For
y \geqslant - x + 2
We test for the origin because, it is not passing through the origin.

0 \geqslant - (0) + 2
This yields
0 \geqslant 2
This statement is false so we shade the upper half.

The intersection is the region shaded in B. The top right graph
8 0
4 years ago
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