Find the equation of the line through point (1,5) and perpendicular to +3=6 x (e.g. 1/2 for 12
1 answer:
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Answer and Step-by-step explanation:
θ
pi r
2x+4y=0
substitute y with 0
2x+4(0)=0
solve the equation
2x+0=0
2x=0
divide by 2 on both sides
x=0
4x+8y=7
substitute y with 0
4x+8(0)=7
solve the equation
4x+0=7
4x=7
divide by 4 on both sides
x=7/4 or x=1 3/4 or x=1.75
3x-7y=-29
2x+2y=6
solve the bottom equation
3x-7y=-29
x=3-y
substitute for x
3(3-y)-7y=-29
solve the equation
y=19/5
now substitute for y
x=3-
solve for x
x=-4/5
the possible solution of the system is the ordered pair
(x,y)=()
Answer:
Step-by-step explanation:
Answer:
a. The amount that is saved at the expiration of the 5 year period is $22,769.20¢
b. The amount of interest is $2,769.20¢
Step-by-step explanation:
Since the amount that is deposited every year for a period of five years is $4,000 and the rate of the interest is 6.5%. We can always calculate the amount that is saved at the expiration of the five years.
We will first state the formula for calculating the future value of annuity:-
Future value of annuity =
Where P is the amount deposited per year.
r is the rate of interest
t is the time or period
and in this case, the actual value of P = $4,000
rate of interest, r is 6.5% = 0.065
time, t is 5 years.
Substituting e, we have:
Fv of annuity =
= 4,000 × [((1.065)^5)- 1/0.065]
= 4,000 × [(1.37 - 1)/0.065]
= 4,000 × (0.37/0.065)
= 4,000 × 5.6923
= $22,769.20¢
a. Therefore the amount that is saved at the end of the five (5) years is $22,769.20¢
b. To find the interest, we will calculate the amount of deposit made during the period of five years and subtract the sum from the current amount that is saved ($22,769.29¢).
Since I deposited 4,000 every year for five years, the total amount of deposit I made at the period =
4,000 × 5 = $20,000
The amount of interest is then = $22,769.20¢ - $20,000 = $2,769.20¢