A thermal reservoir can be characterized as a thermal body that is large enough that when energy is dumped into it or taken out of it, the temperature of the reservoir does not vary considerably.
<h3>What is a thermal reservoir?</h3>
A thermal reservoir is as described, a body large enough to have a very high heat capacity. This heat capacity refers to the amount of energy needed to raise the temperature by one degree.
Therefore, we can confirm that bodies with a large enough heat capacity will be considered thermal reservoirs. This is due to the fact that when energy is dumped into it or taken out of it, the temperature of the reservoir <u>does not vary considerably</u>.
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Answer:
The wavelength of the sound the person observes will be longer than it was, and the frequency will also be lower than it was.
Explanation:
From Doppler effect we know that
f_L= frequency observed by the listener
f_s= frequency of the source
v= velocity of sound
Vs= velocity of source
Vo= velocity of observer
so
when the Source( car siren) moves away, Vs increases and the factor (V -Vs)(V +V_0) decreases
thus f_L also Decreases
option C it is
Answer:
Explanation:
Step 1
1 of 2
\textbf{Given}Given
n_{w}=1.33n
w
=1.33
$\theta_w=31\text{ ^\circ
∘
}$
$\theta_b=27\text{ ^\circ
∘
}$
\textbf{Approach}Approach
In this problem we are going to use Snell's law.
\textbf{Solution}Solution
The definition of Snell's law of refraction is
\begin{align} {n_1\cdot\sin \theta_1}={n_2\cdot \sin \theta_2} \end{align}
n
1
⋅sinθ
1
=n
2
⋅sinθ
2
where indexes 11 and 22 represent two different mediums. Since the motion is in the water we write
\begin{align} &{n_{w}\cdot\sin\theta_{w}}={n_{b}\cdot\sin\theta_{b}} \\ &{n_b}={n_{w}\cdot \frac{\sin\theta_{w}}{ \sin \theta_{b}} } \\ &{n_b}={1.33\cdot \frac{\sin31^\circ}{ \sin27^\circ} } \\ &\boxed{{n_b}=1.5} \end{align}
n
w
⋅sinθ
w
=n
b
⋅sinθ
b
n
b
=n
w
⋅
sinθ
b
sinθ
w
n
b
=1.33⋅
sin27
∘
sin31
∘
n
b
=1.5
Answer:
The magnitude of the force required to bring the mass to rest is 15 N.
Explanation:
Given;
mass, m = 3 .00 kg
initial speed of the mass, u = 25 m/s
distance traveled by the mass, d = 62.5 m
The acceleration of the mass is given as;
v² = u² + 2ad
at the maximum distance of 62.5 m, the final velocity of the mass = 0
0 = u² + 2ad
-2ad = u²
-a = u²/2d
-a = (25)² / (2 x 62.5)
-a = 5
a = -5 m/s²
the magnitude of the acceleration = 5 m/s²
Apply Newton's second law of motion;
F = ma
F = 3 x 5
F = 15 N
Therefore, the magnitude of the force required to bring the mass to rest is 15 N.
The average velocity of the Batman is 0.722 m/s North-East.
<h3>What is average velocity?</h3>
Average velocity can be defined as the ratio of the total displacement to the total time of a body.
To calculate the average velocity of Batman, we use the formula below, first, we need to calculate the resultant displacement of the Batman.
- D = √[(d₁-d₃)²+ (d₂)²]............... Equation 1
Where:
- d₁ = first displacement of the Batman = 6 m North
- d₂ = second displacement of the Batman = 3 m East
- d₃ = third displacement of the Batman. = 4 m south
Substitute these values into equation 1
- D = √[(6-4)²+3²]
- D = √(2²+3²)
- D = √(4+9)
- D = √13
- D = 3.61 m North-East.
To calculate the average velocity, we use the formula below.
- V = D/T............ Equation 2
Where:
- D = 3.61 m North-East
- T = total time = 15 s
Substitute these values into equation 2
- V = 3.61/5
- V = 0.722 m/s North- East.
Hence, the average velocity of the Batman is 0.722 m/s North-East.
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