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mestny [16]
3 years ago
12

A bird flies 1.3 m with an average speed of 2.4m/s How many seconds did the bird fly?

Physics
1 answer:
lord [1]3 years ago
3 0

Answer:

0.54 sec.

Explanation:

The Speed: <u>2.4 m/seconds</u>

The Distance: <u>1.3 m</u>

So time =  Distance/Speed

Time = <u>1.3 / 2.4</u>

THE ANSWER WILL BE 0.54 seconds.

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A man walks along a straight path at a speed of 4 ft/s. A searchlight is located on the ground 6 ft from the path and is kept fo
BARSIC [14]

We are given that,

\frac{dx}{dt} = 4ft/s

We need to find \frac{d\theta}{dt} when x=8ft

The equation that relates x and \theta can be written as,

\frac{x}{6} tan\theta

x = 6tan\theta

Differentiating each side with respect to t, we get,

\frac{dx}{dt} = \frac{dx}{d\theta} \cdot \frac{d\theta}{dt}

\frac{dx}{dt} = (6sec^2\theta)\cdot \frac{d\theta}{dt}

\frac{d\theta}{dt} = \frac{1}{6sec^2\theta} \cdot \frac{dx}{dt}

Replacing the value of the velocity

\frac{d\theta}{dt} = \frac{1}{6} cos^2\theta (4)^2

\frac{d\theta}{dt} = \frac{8}{3} cos^2\theta

The value of cos \theta could be found if we know the length of the beam. With this value the equation can be approximated to the relationship between the sides of the triangle that is being formed in order to obtain the numerical value. If this relation is known for the value of x = 6ft, the mathematical relation is obtained. I will add a numerical example (although the answer would end in the previous point) If the length of the beam was 10, then we would have to

cos\theta = \frac{6}{10}

\frac{d\theta}{dt} = \frac{8}{3} (\frac{6}{10})^2

\frac{d\theta}{dt} = \frac{24}{25}

Search light is rotating at a rate of 0.96rad/s

4 0
3 years ago
A rabbit with a mass of 2.0 kg accelerates at 2.0 meters per second squared. Find the net force of the rabbit
scZoUnD [109]

Answer:

4N

Explanation:

Force = mass x acceleration

Given

Mass = 2.0kg

Acceleration = 2.0m/s^2

Force = 2.0 x 2.0

= 4N

5 0
4 years ago
Read 2 more answers
Why do you think the cup that is exposed to more air has water outside it?
mylen [45]
It's called condensation. That is what that wetness on the outside of the cup is.
6 0
3 years ago
At what height does a 1000-kg mass have potential energy of 1J relative to the ground?
Dvinal [7]

Answer:

0.0001 m

Explanation:

Given

M=1000 KG

PE=1 J

G=9.8 m/s

H=?

Formula

PE = MGH

H= PE/MG

H=1/1000x9.8

H= 1/9800

or 0.00010204

7 0
3 years ago
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Mila [183]
The answers to question 4 d
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