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andrew-mc [135]
3 years ago
9

A thermal reservoir can be characterized as a thermal body that is large enough that when energy is dumped into it or taken out

of it, the __ of the reservoir does not vary considerably. The answer is an 11 letter word that begins with t and ends with e.
Physics
2 answers:
Ganezh [65]3 years ago
8 0

It should be noted that thermal reservoir is been characterized as a thermal body which is large enough and the removal of energy or dumping of it into it , the temperature of the reservoir does not vary considerably.

The thermal reservoir helps in the storage of energy, and it allows the removal as well as supplying of energy into it , however the temperature difference is not usually much.

Therefore, Temperature is the correct term.

learn more about thermal reservoir at;

brainly.com/question/13154260

hammer [34]3 years ago
7 0

A thermal reservoir can be characterized as a thermal body that is large enough that when energy is dumped into it or taken out of it, the temperature of the reservoir does not vary considerably.

<h3>What is a thermal reservoir?</h3>

A thermal reservoir is as described, a body large enough to have a very high heat capacity. This heat capacity refers to the amount of energy needed to raise the temperature by one degree.

Therefore, we can confirm that bodies with a large enough heat capacity will be considered thermal reservoirs. This is due to the fact that when energy is dumped into it or taken out of it, the temperature of the reservoir <u>does not vary considerably</u>.

To learn more about heat capacity visit:

brainly.com/question/1453843?referrer=searchResults

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Answer:

Atomic Size and Mass:

convert given density to kg/m^3 = 8900kg/m^3 2) convert to moles/m^3 (kg/m^3 * mol/kg) = 150847 mol/m^3 (not rounding in my actual calculations) 3) convert to atoms/m^3 (6.022^23 atoms/mol) = 9.084e28 atoms/m^3 4) take the cube root to get the number of atoms per meter, = 4495309334 atoms/m 5) take the reciprocal to get the diameter of an atom, = 2.2245e-10 m/atom 6) find the mass of one atom (kg/mol * mol/atoms) = 9.7974e-26 kg/atom Young's Modulus: Y=(F/A)/(dL/L) 1) F=mg = (45kg)(9.8N/kg) = 441 N 2) A = (0.0018m)^2 = 3.5344e-6 m^2 3) dL = 0.0016m 4) L = 2.44m 5) Y = 1.834e11 N/m^2 Interatomic Spring Stiffness: Ks,i = dY 1) From above, diameter of one atom = 2.2245e-10 m 2) From above, Y = 1.834e11 N/m^2 3) Ks,i = 40.799 N/m (not rounding in my actual calculations) Speed of Sound: v = ωd 1) ω = √(Ks,i / m,a) 2) From above, Ks,i = 40.799 N/m 3) From above, m,a = 9.7974e-26 kg 4) ω=2.0406e13 N/m*kg 5) From above, d=2.2245e-10 m 6) v=ωd = 4539 m/s (not rounding in actual calculations) Time Elapsed: 1) length sound traveled = L+dL = 2.44166 m 2) From above, speed of sound = 4539 m/s 3) T = (L+dL)/v = 0.000537505 s

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X-Rays at different wavelengths provide scientists studying objects in space with information about which of the following?
olganol [36]

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Explanation:

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Reika [66]

Complete question:

The coordinate of a particle in meters is given by x(t)=1 6t- 3.0t³ , where the time tis in seconds. The

particle is momentarily at rest at t is:

Select one:

a. 9.3s

b. 1.3s

C. 0.75s

d.5.3s

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​

Answer:

b. 1.3 s

Explanation:

Given;

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16 - 9t² = 0

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Answer:

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