T<span>he phenomenon of </span>static electricity<span> requires a separation of </span>positive<span> and </span>negative<span> charges. When two materials are in contact, electrons may move from one material to the other, which leaves an excess of </span>positive<span>charge on one material, and an equal </span>negative<span> charge on the other.</span>
Deceleration isn't a term in physics; you can have positive acceleration which is speeding up and negative acceleration which is slowing down
Use newton's law F = ma
a = F/m
Question: Initially, the car travels along a straight road with a speed of 35 m/s. If the brakes are applied and the speed of the car is reduced to 13 m/s in 17 s, determine the constant deceleration of the car.
Answer:
1.29 m/s²
Explanation:
From the question,
a = (v-u)/t............................ Equation 1
Where a = deceleration of the car, v = final velocity of the car, u = initial velocity of the car, t = time.
Given: v = 13 m/s, u = 35 m/s, t = 17 s.
a = (13-35)/17
a = -22/17
a = -1.29 m/s²
Hence the deceleration of the car is 1.29 m/s²
Answer:
L
Explanation:
For every action, there is an equal and opposite reaction.
As the moment of inertia if the gyroscope is 1/10 of that of the remainder of the satellite, the angular velocity of the satellite will be 1/10 that of the spun up gyroscope and in the opposite direction.
L = Iω
