Answer:
aldehyde
Explanation:
Aldehydes are a large class of reactive organic compounds (R-CHO) having a carbonyl functional group attached to one hydrocarbon radical and a hydrogen atom.
So, when terminal alkynes, for example, 1-heptyne react on Hydroboration oxidation(i.e. disiamylborane followed by treatment with basic hydrogen peroxide), the formation of aldehyde occurs.
First, we determine the mass of each element from the data collected. We can get the mass of molybdenum Mo from the difference between the mass of crucible and molybdenum and the mass of crucible:
Mass of molybdenum = 39.52 – 38.26 = 1.26 g Mo
We can calculate for the mass of molybdenum oxide from the difference between the mass of crucible and molybdenum oxide and the mass of crucible:
Mass of molybdenum oxide = 39.84 – 38.26 = 1.58g
We can now compute for the mass of oxygen O by subtracting the mass of molybdenum from the mass of molybdenum oxide:
Mass of oxygen in molybdenum oxide = 1.58 – 1.26 = 0.32g O
To convert mass to moles, we use the molar mass of each element.
1.26 g Mo * 1 mol Mo / 95.94 g Mo = 0.0131 mol Mo
0.32 g O * 1 mol O / 15.999 g O = 0.0200 mol O
0.0131 mol is the smallest number of moles. We divide each mole value by this number:
0.0131 mol Mo / 0.0131 = 1
0.0200 mol O / 0.0131 = 1.53
Multiplying these results by 2 to get the lowest whole number ratio,
0.0131 mol Mo / 0.0131 = 1 * 2 = 2
0.0200 mol O / 0.0131 = 1.5 * 2 = 3
Thus, we can write the empirical formula as Mo2O3.
Answer:
Explanation:
8.73 mol x mol
2 C57H110O6(S) + 163 O2(g) ---> 114 CO2(g) + 110 H2O(I)
2 mol 114 mol
8.78 mol (114mol/2 mol) =500.46 mol
Answer:
2
Explanation:
Each orbital can hold two electrons. One spin-up and one spin-down.
