An object has a density of 2.0g/cm3. If the object were cut in half what would be the density of one of the pieces?

Carnegie Development stages

Darya [45]

Answer:

Stage 1: 1 days.

Stage 2: 2-3 days.

Stage 3: 4-5 days.

Stage 4: 6 days.

Stage 5 (a-c): 7-12 days.

Stage 6: c. 17 days.

Stage 7: c. 19 days.

Stage 8: c. 23 days.

7 0

3 years ago

One way of obtaining pure sodium carbonate is through the decomposition of the mineral trona, Na3(CO3)(HCO3)·2H2O. 2Na3(CO3)(HCO

zhenek [66]

Percentage yield = (actual yield / theoretical yield) x 100%

The balanced equation for the decomposition is,
2Na₃(CO₃)(HCO₃)·2H₂O(s) → 3Na₂CO₃(s) + CO₂(g) + 5H₂<span>O(g)

The stoichiometric ratio between </span>Na₃(CO₃)(HCO₃)·2H₂O(s) and Na₂CO₃(s) is 2 : 3

The decomposed mass of Na₃(CO₃)(HCO₃)·2H₂O(s) = 1000 kg
= 1000 x 10³ g

Molar mass of Na₃(CO₃)(HCO₃)·2H₂O(s) = 226 g mol⁻¹
moles of Na₃(CO₃)(HCO₃)·2H₂O(s) = mass / molar mass
= 1000 x 10³ g / 226 g mol⁻¹
= 4424.78 mol

Hence, moles of Na₂CO₃ formed = 4424.78 mol x $\frac{3}{2}$
= 6637.17 mol

Molar mass of Na₂CO₃ = 106 g mol⁻¹

Hence, mass of Na₂CO₃ = 6637.17 mol x 106 g mol⁻¹
= 703540.02 g
= 703.540 kg

Hence, the theoretical yield of Na₂CO₃ = 703.540 kg
Actual yield of Na₂CO₃ = 650 kg

Percentage yield = (650 kg / 703.540 kg) x 100%
= 92.34%

7 0

3 years ago

Can u plz give an answer to me thank you

vagabundo [1.1K]

The puppies have different colored noses because of reccesive and dominant genotypes.

Genotypes are represented by letters, capital being dominant and lowercase being recessive.

For example, lets say t = pink nose and T = black nose.

If the parents have black noses, then they will pass on T genotypes.

But, they also have hidden pink nose genotypes.

These hidden genotypes are passed on to the puppies, one of the puppies gets more black nose genotypes.

If a puppy gets tt, they will have a pink nose.

If they get TT, they will have a black nose

If they get Tt, they will also have a black nose.

Because the black nose is dominant, its more likley for the puppies to end up with a black nose.

4 0

3 years ago

During the naval battles of the South Pacific in World War II, the U.S. Navy produced smoke screens by spraying titanium tetrach

hammer [34]

Explanation:

The reaction given is;

TiCl4 + H2O --> TiO2 + HCl

The reaction is not balanced, upon balancing it is given as;

TiCl4 + 2H2O → TiO2 + 4HCl

a. How many moles of H2O are needed to react with 6.50 moles of TiCl4?

From the reaction;

1 mol of TiCl4 requires 2 mol of H2O

6.50 mol of TiCl4 would require x mol of H2O

1 = 2

6.5 = x

x = 6.5 * 2 / 1 = 13.0 mol

b. How many moles of HCl are formed when 8.44 moles of TiCl4 react?

From the equation of the reaction;

1 mol of TiCl4 reacts to form 4 mol of HCl

8.44 mol of TiCl4 reacts to form x mol of HCl

1 = 4

8.44 = x

x = 8.44 * 4 / 1 = 33.76 mol

4 0

3 years ago

A balloon that had a volume of 3.50 L at 25.0°C is placed in a hot room at 40.0°C. If the pressure remains constant at 1.00 atm,

inna [77]

Answer:

3.676 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and P are constant, and have different values of V and T:

(V₁T₂) = (V₂T₁)

Knowing that:

V₁ = 3.5 L, T₁ = 25°C + 273 = 298 K,

V₂ = ??? L, T₂ = 40°C + 273 = 313 K,

Applying in the above equation

(V₁T₂) = (V₂T₁)

∴ V₂ = (V₁T₂)/(T₁) = (3.5 L)(313 K)/(298 K) = 3.676 L.

7 0

3 years ago

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