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3 years ago

7

How does an atom become a positively charged ion? by gaining one or more electrons by gaining one or more neutrons by losing one

or more electrons by losing one or more neutrons

1 answer:

erma4kov [3.2K]3 years ago

4 0

By losing one or more electrons

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air in a closed container with a fixed volume is heated from 25 c to 36 c if the pressure is initially at 3.8atm what would the

Nikitich [7]

P1T2 = P2T1
(3.8)(36)=25P2
136.8=25P2
136.8/25=P2
P2=5.472atm

8 0

3 years ago

Drug testing of athletes and other individuals is big business.

ziro4ka [17]

Answer:

bioanalytical chemistry

Explanation:

7 0

3 years ago

A hydrocarbon contains 85.7% carbon and the remainder

Viefleur [7K]

Answer:

CH₂ ; 67.1 %

Explanation:

To determine the empirical formula we need to find what the mole ratio is in whole numbers of the atoms in the compound. To do that we will first need the atomic weights of C and H and then perform our calculation

Assume 100 grams of the compound.

# mol C = 85.7 g / 12.01 g/mol = 7.14 mol

# mol H = 14.3 g / 1.008 g/mol = 14.19 mol

The proportion is 14.9 mol H/ 7.14 mol C = 2 mol H/ 1 mol C

So the empirical formula is CH₂

For the second part we will need to first calculate the theoretical yield for the 12.03 g NaBH₄ reacted and then calculate the percent yield given the 0.295 g B₂H₆ produced.

We need to calculate the moles of NaBH₄ ( M.W = 37.83 g/mol )

1.203 g NaBH₄ / 37.83 g/mol = 0.0318 mol

Theoretical yield from balanced chemical equation:

0.0318 mol NaBH₄ x 1 mol B₂H₆ / mol NaBH₄ = 0.0159 mol B₂H₆

Theoretical mass yield B₂H₆ = 0.0159 mol x 27.66 g/ mol = 0.440 g

% yield = 0.295 g/ 0.440 g x 100 = 67.1 %

6 0

3 years ago

Find [cu2+] in a solution saturated with cu4(oh)6(so4) if [oh − ] is fixed at 2.3 ✕ 10−6 m. note that cu4(oh)6(so4) gives 1 mol

ki77a [65]

<span>

</span> $Cu_4(OH)_6(SO_4)$
<span>
You have OH- conc = </span>2.3 ✕ 10−6 m
From the formula, you can observe the ratio of Cu2+ to OH- is 4 : 6 = 2:3

So, for 2.3 ✕ 10−6 m OH-
[Cu2+] = $\frac{2}{3} \times 2.3 \times 10^{-6}$

$= 1.53 \times 10^{-6} 
$

6 0

3 years ago

What is the partial pressure of radon if the total pressure is 780 torr and the

Brilliant_brown [7]

Answer:

0.03atm

Explanation:

Given parameters:

Total pressure = 780torr

Partial pressure of water vapor = 1.0atm

Unknown:

Partial pressure of radon = ?

Solution:

A sound knowledge of Dalton's law of partial pressure will help solve this problem.

The law states that "the total pressure of a mixture of gases is equal to the sum of the partial pressures of the constituent gases".

Mathematically;

P $_{t}$ = P $_{1}$ + P $_{2}$ + P $_{n}$

Since the total pressure is 780torr, convert this to atm;

760torr = 1 atm

780torr = $\frac{780}{760}$ atm = 1.03atm

For this problem;

Total pressure = Partial pressure of radon + Partial pressure of water vapor

1.03 = Partial pressure of radon + 1.0

Partial pressure of radon = 1.03 - 1.00 = 0.03atm

6 0

3 years ago