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icang [17]
2 years ago
11

Two reasons why a scientist might want to study the DNA of strawberries?

Chemistry
2 answers:
ElenaW [278]2 years ago
5 0

Following are the two reasons.

They can figure out how the preparations collected in DNA help your body to perform properly. They can use DNA to make modern medicines or genetically transform crops to be resistant to insects. Strawberries are a very marketable horticultural crop. They do experience from disease and insect attacks, are responsive to heat and cold and prefer a comparatively close range of soil types for best production.

The study of strawberry DNA may provide the plant breeder with keys to thriving strategies to master these and many other restrictions for the strawberry product.

fenix001 [56]2 years ago
3 0
1.To discover the chromosomal state of the species in order to advance on Knowledge of the species Evolutionary process.
2. To form a hybrid of the species.
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In your own words what is equilibrium?
fenix001 [56]

Answer:

when the forward and reverse reactions occur at equal rates.

chemical reaction is in equilibrium when the concentrations of reactants and products are constant - their ratio does not vary.

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3 years ago
Fe2(SO4)3 +__BaCl2 → __BaSO4 +_<br> FeCl3
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Answer:

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2.Which of the alcohols listed below would you expect to react most rapidly with PBr3?A)CH3CH2CH2CH2CH2CH2OHB)(CH3CH2)2CH(OH)CH2
Gnoma [55]

Answer:

A) CH3CH2CH2CH2CH2CH2OH

Explanation:

For this question, we have the following answer options:

A) CH3CH2CH2CH2CH2CH2OH

B) (CH3CH2)2CH(OH)CH2CH3

C) (CH3CH2)2CHOHCH3

D) (CH3CH2)3COH

E) (CH3CH2)2C(CH3)OH

We have to remember the<u> reaction mechanism</u> of the substitution reaction with PBr_3. <em>The idea is to generate a better leaving group in order to add a "Br" atom.</em>

The PBr_3 attacks the "OH" generation new a bond to P (O-P bonds are very strong), due to this new bond we will have a better leaving group that can remove the oxygen an allow the attack of the Br atom to generating a new C-Br bond. This is made by an <u>Sn2 reaction</u>. Therefore we will have a faster reaction with <u>primary substrates</u>. In this case, the only primary substrate is molecule A. So, <em>"CH3CH2CH2CH2CH2CH2OH"</em> will react faster.

See figure 1

I hope it helps!

7 0
3 years ago
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