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icang [17]
3 years ago
11

Two reasons why a scientist might want to study the DNA of strawberries?

Chemistry
2 answers:
ElenaW [278]3 years ago
5 0

Following are the two reasons.

They can figure out how the preparations collected in DNA help your body to perform properly. They can use DNA to make modern medicines or genetically transform crops to be resistant to insects. Strawberries are a very marketable horticultural crop. They do experience from disease and insect attacks, are responsive to heat and cold and prefer a comparatively close range of soil types for best production.

The study of strawberry DNA may provide the plant breeder with keys to thriving strategies to master these and many other restrictions for the strawberry product.

fenix001 [56]3 years ago
3 0
1.To discover the chromosomal state of the species in order to advance on Knowledge of the species Evolutionary process.
2. To form a hybrid of the species.
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You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.8
Lubov Fominskaja [6]

Complete Question

You determine that it takes 26.0 mL of base to neutralize a sample of your unknown acid solution. The pH of the solution was 7.82 when exactly 13 mL of base had been added, you notice that the concentration of the unknown acid was 0.1 M. What is the pKa of your unknown acid?

Answer:

The pK_a value is pK_a  =7.82

Explanation:

From the question we are told

    The volume of base is  V_B = 26.mL = 0.0260L

     The pH of solution is  pH =  7.82

      The concentration of the acid is C_A = 0.1M

From the pH we can see that the titration is between a strong base and a weak acid

 Let assume that the the volume of acid is  V_A = 18mL= 0.018L

Generally the concentration of base

                    C_B = \frac{C_AV_A}{C_B}

Substituting value  

                     C_B = \frac{0.1 * 0.01800}{0.0260}

                    C_B= 0.0692M

When 13mL of the base is added a buffer is formed

The chemical equation of the reaction is

           HA_{(aq)} + OH^-_{(aq)} --------> A^{+}_{(aq)} + H_2 O_{(l)}

Now before the reaction the number of mole of base is  

            No \ of \ moles[N_B]  =  C_B * V_B

Substituting value  

                    N_B = 0.01300 * 0.0692

                         = 0.0009 \ moles    

                                 

Now before the reaction the number of mole of acid is  

            No \ of \ moles  =  C_B * V_B

Substituting value  

                    N_A = 0.01800 *0.1

                         = 0.001800 \ moles

Now after the reaction the number of moles of  base is  zero  i.e has been used up

    this mathematically represented as

                         N_B ' = N_B - N_B = 0

    The  number of moles of acid is  

             N_A ' = N_A  - N_B

                   = 0.0009\ moles

The pH of this reaction can be mathematically represented as

                 pH  = pK_a + log \frac{[base]}{[acid]}

Substituting values

                  7.82 = pK_a +log \frac{0.0009}{0.0009}

                  pK_a  =7.82        

                     

             

                                 

       

           

                     

8 0
3 years ago
Oxidation number of sulphur in H2SO4
DochEvi [55]

Answer

let the oxidation of sulphur is x

2(+1)+x+4(-2)=0

+2+x-8=0

+2-8+x=0

-6+x=0

x=6

Explanation:

i hope this will help you:)

8 0
3 years ago
a solid sample of oil is warmed until it turns into a liquid. which property of the oil will decrease?
raketka [301]

  I think the answer is it turnes into a gas. Hope it helps! :) Asnwer is density.

4 0
3 years ago
What is the mass percentage of O in C₂H₄O₂? Provide an answer to two decimal places.
nasty-shy [4]

Answer:

53.29%

Explanation:

The molar mass of C2H4O2 is 60.05g and the 2 O's are 32.00g

so 32.00/60.05= 0.53288925895

and that as a decimal rounded to the nearest hundredths is 53.29%

6 0
2 years ago
5. What is the number value of absolute zero? *<br> (
Norma-Jean [14]

Answer:

0

Explanation:

it is 0 I believe nothing

7 0
2 years ago
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