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icang [17]
3 years ago
11

Two reasons why a scientist might want to study the DNA of strawberries?

Chemistry
2 answers:
ElenaW [278]3 years ago
5 0

Following are the two reasons.

They can figure out how the preparations collected in DNA help your body to perform properly. They can use DNA to make modern medicines or genetically transform crops to be resistant to insects. Strawberries are a very marketable horticultural crop. They do experience from disease and insect attacks, are responsive to heat and cold and prefer a comparatively close range of soil types for best production.

The study of strawberry DNA may provide the plant breeder with keys to thriving strategies to master these and many other restrictions for the strawberry product.

fenix001 [56]3 years ago
3 0
1.To discover the chromosomal state of the species in order to advance on Knowledge of the species Evolutionary process.
2. To form a hybrid of the species.
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Will give brainliest this is simple plz help
julsineya [31]

Answer:

IIron is the 26th element on the periodic table. It is located in period 4 and group 8. And for the properties, iron, like other metals, conducts heat and electricity, has a luster, and forms positive ions in its chemical reactions. Pure iron is fairly soft and can easily be shaped and formed when hot. Its color is silvery white. Iron is easily magnetized.

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4 0
3 years ago
The number of protons plus the number of neutrons in an atom is called its 7 number. for carbon-12, this number is
emmasim [6.3K]
The mass of Carbon-12 is 12.
8 0
3 years ago
Please can you help me with this ​
vlabodo [156]

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C. Pulley.

Explanation:

8 0
3 years ago
What is the limiting reactant if 12 moles of p4 react with 15 moles of o2?.
brilliants [131]

Answer:

see explanation

Explanation:

To determine limiting reactant divide mole quantities of reactants by the respective coefficient in the balanced equation. The smaller value is the limiting reactant.

    P₄      +     5O₂       => 2P₂O₅

12/1 = 12      15/5 = 3

O₂ is the limiting reactant. P₄ will be in excess when rxn stops.

4 0
2 years ago
A 52.0-mL volume of 0.35 M CH3COOH (Ka=1.8×10−5) is titrated with 0.40 M NaOH. Calculate the pH after the addition of 23.0 mL of
Georgia [21]

NaOH reacts with CH3COOH in 1:1 molar ratio to produce CH3COONa 

NaOH + CH3COOH → CH3COONa + H2O 

Mol CH3COOH in 52.0mL of 0.35M solution = 52.0/1000*0.35 = 0.0182 mol CH3COOH 

Mol NaOH in 19.0mL of 0.40M solution = 19.0/1000*0.40 = 0.0076 mol NaOH 

These will react to produce 0.0076 mol CH3COONa and there will be 0.0182 - 0.0076 = 0.0106 mol CH3COOH remaining in solution unreacted . Total volume of solution = 52.0+19.0 = 71mL or 0.071L 

Molarity of CH3COOH = 0.0106/0.071 = 0.1493M 

CH3COONa = 0.0076 / 0.071 = 0.1070M 

pKa acetic acid = - log Ka = -log 1.8*10^-5 = 4.74. 

pH using Henderson - Hasselbalch equation: 

pH = pKa + log ([salt]/[acid]) 

pH = 4.74 + log ( 0.1070/0.1493) 

pH = 4.74 + log 0.717 

pH = 4.74 + (-0.14) 

pH = 4.60.

7 0
3 years ago
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