Answer:
90.37 g
Explanation:
From Avogadro Number,
1 mole of every substance contains a particle number of 6.02×10²³
From the question,
1 mole of CH₄ contains 6.02×10²³ molecules.
But,
1 mole of CH₄ has a mass of 16 g
Therefore,
16 g of CH₄ contains 6.02×10²³ molecules
Then,
Y g will contain 3.4×10²⁴ molecules
Solve for Y
Y = (16× 3.4×10²⁴)/(6.02×10²³)
Y = 90.37 g
The simplest formula for a compound made from element x which is molar mass is equals to 79.0 g/mol that is 21% nitrogen by mass is X sub 2 N sub 3. In addition, X is equals to 79.0 and N is equals to 14.
Using ideal gas equation,
PV=nRT
P=199 kpa
V=4.67 L
T=30+273K= 303K
n= number of moles of gas
R=8.321 L·kPa·K-1·mol-1
So using ideal gas equation,
n=PV/RT
=199*4.67/8.321*303\
=0.37 mol
Answer:
Covalent bobd
Explanation:
Chamical bonding between non metals is covalent.
Answer:
After increasing the volume, we have 1.81 moles of hydrogen gas in the container
Explanation:
Step 1: Data given
Number of moles hydrogen gas (H2) = 1.24 moles
Volume of hydrogen gas (H2° = 27.8 L
The final volume is increas to 40.6 L
Step 2: Calculate the new number of moles
V1/n1 = V2/n2
⇒with V1 = the initial volume = 27.8 L
⇒with n1 = the initial number of moles H2 = 1.24 moles
⇒with V2 = the final volume = 40.6 L
⇒with n2 = the new number of moles = TO BE DETERMINED
27.8L / 1.24 moles = 40.6 L / n2
n2 = 40.6 / (27.8/1.24)
n2= 1.81 moles
After increasing the volume, we have 1.81 moles of hydrogen gas in the container
