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3 years ago

Rectangle has a perimeter of 48". The length is 4" more than the width. What is the length?

Mathematics

2 answers:

Svetradugi [14.3K]3 years ago

3 0

Answer:

If you don't know it off the top of your head, work backwards.

48/4=12

Check:

12(4)=48

SVETLANKA909090 [29]3 years ago

3 0

Answer:

Length equals 14

Step-by-step explanation:

This problem can be written out as 2 equations

Since we know the perimeter (P) is 48, we can use the formula 2l+2w=P and get 2l+2w=48.

Then we can take the other equation, w+4=l (which I got from the second sentence), and substitute it for l in the equation.

This can be written out as- 2(w+4) + 2w=48

Then we distribute and get 2w + 2w + 8 = 48, simplifying to 4w + 8= 48

We then subtract 8 from 48 and get 4w=40, dividing 40 by 4 to get w=10.

then, we add 4 to w to get 14.

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Step-by-step explanation:

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PLEASE HELP<br><br>divide. (3x-2)(x-4)-(x-4)(6-5x)<br>/(4-x)(8x-1)

8_murik_8 [283]

Answer:

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Step-by-step explanation:

Solve for x:

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Simplify and substitute y = 4 - x.

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Divide both sides by -37:

y^2 - (257 y)/37 + 434/37 = 0

Subtract 434/37 from both sides:

y^2 - (257 y)/37 = -434/37

Add 66049/5476 to both sides:

y^2 - (257 y)/37 + 66049/5476 = 1817/5476

Write the left hand side as a square:

(y - 257/74)^2 = 1817/5476

Take the square root of both sides:

y - 257/74 = sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Add 257/74 to both sides:

y = 257/74 + sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

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Subtract 4 from both sides:

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Multiply both sides by -1:

x = 39/74 - sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Add 257/74 to both sides:

x = 39/74 - sqrt(1817)/74 or y = 257/74 - sqrt(1817)/74

Substitute back for y = 4 - x:

x = 39/74 - sqrt(1817)/74 or 4 - x = 257/74 - sqrt(1817)/74

Subtract 4 from both sides:

x = 39/74 - sqrt(1817)/74 or -x = -39/74 - sqrt(1817)/74

Multiply both sides by -1:

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