Need help in this please

An electronics store makes a profit of $72 for every standard CD player sold and $90 for every portable CD sold. the managers ta

Alisiya [41]

s -> no: of standard CD players sold

p -> no: of portable CD players sold.

Profit Per Standard CD player=72$

Profit per Portable CD player =90$

Target Amount =360$

In short: The combined sales of Both the CD player's must exceed or atleast become equal to 360$ to acquire the target.

Thus; the inequality can be stated as:

 72(s) + 90(p) ≥360

-> 36(s) + 45(p) ≥180

-> 12(s) +15(p) ≥ 90

 _______________

->| 4(s) + 5(p) ≥ 30 |

Hope it helps...

Hope it helps...Regards;

Hope it helps...Regards;Leukonov/Olegion.

8 0

3 years ago

If you wanted to make the graph of y=5x+3 les steep, which equation could you use?

stepan [7]

B

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = 5x + 3 is in this form with slope m = 5

To decrease the slope we require a smaller, positive value for m

y = x + 3 has m = 1 which is less than 5 and positive

y = x + 3 is less steep than y = 5x + 3

6 0

3 years ago

20/10 as a mixed number

Minchanka [31]

20/10 as a mixed number:

20 ÷ 10 = 2.

10 goes into 20 two times. So 20/10 as a mixed number is a whole number: 2.

20/10 = 2

3 0

3 years ago

Read 2 more answers

HELPPP ME PLEASEeeeeee

Korvikt [17]

Answer:

4.116 × 10^8 = 411,600,000

Step-by-step explanation:

i just put it in the calculator dont get mad at me

4 0

2 years ago

Read 2 more answers

three-quarters of a pile of bricks were used for a certain project. when two thirds of the reminder had been used, 50 bricks wer

kati45 [8]

Answer:

600

Step-by-step explanation:

Let's consider this question using algebra.

Imagine the number of bricks in the original pile is $x$ .

We are told that $\frac{3}{4}$ of the bricks are used for a project, meaning that $\frac{3}{4} x$ has been used, leaving us with $\frac{1}{4}x$ as our remainder.

Then, we are told that $\frac{2}{3}$ of the remainder are used to leave us with 50 bricks. This means that $\frac{1}{3}$ of the remainder is left, and this is equal to 50 bricks. This means that the remainder's original amount is equal to 150, because we are told that $\frac{1}{3}$ of the remainder is equal to 50.

So, we know that the remainder is 150, and we also know that the remainder is $\frac{1}{4} x$ . Let's now use these to form an equation.

$\frac{1}{4} x = 150$

Because we know that a quarter of the original amount of bricks is equal to 150, we can multiply both sides of the equation by 4 to get the original amount of bricks in the pile.

$x = 150 * 4 = 600$

So, there were 600 bricks in the original pile.

8 0

2 years ago

Need help in this please​

Need help in this please