Answer:
Surface area of Cube Y is 3 times greater than the surface area of cube X
Step-by-step explanation:
Surface area of a cube,A = 6s²
Where,
s = side length
Cube X has a side length of 1,
Surface area of cube, X = 6s²
= 6 * 1²
= 6 * 1
= 6
cube Y has a side length of 2
Surface area of cube, Y = 6s²
= 6 * 2²
= 6 * 4
= 24
How much greater is the surface area of cube Y than cube X?
Surface area of Cube Y is 3 times greater than the surface area of cube X
The answer is C, they are congruent because they are alternate interior angles
Answer:
x^2 - 6x + 147 so the coefficient is 1
Step-by-step explanation:
First, simplify the equation.
1. 2/3x(2x-3) = (2x/3)(2x-3)-(x-7)(x+7)
2. 2x-3(2x/3) = (2x(2x-3)) - (x-7)(x+7)
3. Expand -(x-7)(x+7) = -x^2+49
Combine to get (x^2 - 6x)/3 +49
Simplify to get x^2 - 6x + 147. The coefficient of the quadratic term is one.
Answer: see below
Step-by-step explanation:
|2x+5|=7
2x+5=±7 ⇔ since the absolutely value of any number is all positive, so the value in side can be either positive or negative
2x+5=7 or 2x+5=-7
2x=2 2x=-12
x=1 or x=-6
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The product of the two solutions
1 × -6=-6
Hope this helps!! :)
Please let me know if you have any question
The answer is a because 552.50 x .12 is 66.30. 66.30 minus 552.50 is 486.50 and that divided by 7 is 69.45
