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3 years ago

3+{2×(8-4+6)}-5-{9+4-[3×(1-5)]}

Mathematics

1 answer:

Nadya [2.5K]3 years ago

3 0

Answer:

Step-by-step explanation:

Alright all we need to know is to understand our brackets

So 3+{2×(8-4+6)}-5-{9+4-[3×(1-5)]}

3+20-5-9+4-3(1-5)

Step 2

3+20-5-9+4-3(1-5) Simplify

18-9+4-3(1-5)

Step 3

18-9+4-3(1-5)

13-3(1-5)

13-(-12) Here is the tricky part (We aren't going to subtract because the brackets multiply the equations

So,

13+12=25

Your answer is 25

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Divide the fractions. thank ya'll super much. (lol) =P

Darina [25.2K]

Answer:

1 4/21

Step-by-step explanation:

5/6 * 10/7

5/3 * 5/7

25/21

1 4/21

8 0

3 years ago

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Simplify the expression. Explain each step.<br> - q•3

Sveta_85 [38]

Answer:

-3q

Step-by-step explanation:

-q is actually -1q so you just divide 3 by -1 and get -3q

8 0

3 years ago

How do you solve 10(z-2)=1+4

tamaranim1 [39]

I'm assuming you want us to solve for the unknown variable z

$10(z-2)=1+4$

Combine like terms on the right side

$10(z-2)=5$

Use the distributive property on the left side

$10z-20=5$

Add both sides by 20 to cancel out the "-20" on the left side

$10z=25$

Divide both sides by 10

$z=2.5$

That is the value of the known variable, z, in this equation. Let me know if you need any clarifications, thanks!

~ Padoru

6 0

3 years ago

Read 2 more answers

2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):

zlopas [31]

<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

$A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)$

First pair of opposite sides:

<u>Slope:</u>

$\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}$

Second pair of opposite sides:

<u>Slope:</u>

$\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}$

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

$d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\$

So the diagonals measure the same, therefore this is a rectangle.

5 0

3 years ago

The rectangles garden is 25ft by 15ft what is the area of the garden ?

steposvetlana [31]

I hope this helps you

Area=25x15

Area=375

8 0

3 years ago

3+{2×(8-4+6)}-5-{9+4-[3×(1-5)]}​

3+{2×(8-4+6)}-5-{9+4-[3×(1-5)]}