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Komok [63]
2 years ago
8

Suppose that a1, a2, a3, . . . is an arithmetic sequence, in which a3 = 19 and a14 = 96. Find a1.

Mathematics
1 answer:
katovenus [111]2 years ago
7 0
Uhhh I think you have to add 19 and 14 which shall give you the answer to a1 so it should be 33 but then I think you divide 33 and 96 or you will multiply 33 and 96
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vichka [17]
75d+8w+25
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3 years ago
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Wewaii [24]

Answer:

6.7 cm

Step-by-step explanation:

To make use of the Law of Sines for finding b, you need to know the missing angle B. Since the sum of the angles of a triangle is 180°, you can find angle B as ...

B = 180° -82° -55° = 43°

Now, you put the numbers you know into the formula given and solve for b.

sin(A)/a = sin(B)/b

sin(55°)/(8 cm) = sin(43°)/b

Cross multiplying gives ...

b·sin(55°) = (8 cm)·sin(43°)

and dividing by the coefficient of b gives you ...

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4 0
3 years ago
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andriy [413]

Answer:

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Step-by-step explanation:

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