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2 years ago

11

Please help with math and explain if u do i’ll give brainly!!

1 answer:

Nikolay [14]2 years ago

3 0

Answer:

3/2

Step-by-step explanation:

MNOP to ABCD: The answer has to be greater than one because ABCD increases in size from MNOP.

To get the scale factor you have to compare the sides.

Line AD = 6 in.

Line MP = 4 in.

6/4 = 3/2

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which inequality does the graph represent??? if you could answer that would greatly be appreciated (∧_∧)

tiny-mole [99]

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I hope this helps love! :)

8 0

3 years ago

A golfer hits an errant tee shot that lands in the rough. A marker in the center of the fairway is 150 yards from the center of

Gwar [14]

$\bold{\huge{\underline{ Solution}}}$

<h3><u>Given </u><u>:</u><u>-</u></h3>

A marker in the center of the fairway is 150 yards away from the centre of the green
While standing on the marker and facing the green, the golfer turns 100° towards his ball
Then he peces off 30 yards to his ball

<h3><u>To </u><u>Find </u><u>:</u><u>-</u></h3>

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>distance </u><u>between </u><u>the </u><u>golf </u><u>ball </u><u>and </u><u>the </u><u>center </u><u>of </u><u>the </u><u>green </u><u>.</u>

<h3><u>Let's </u><u> </u><u>Begin </u><u>:</u><u>-</u></h3>

Let assume that the distance between the golf ball and central of green is x

<u>Here</u><u>, </u>

Distance between marker and centre of green is 150 yards
<u>That </u><u>is</u><u>, </u>Height = 150 yards
For facing the green , The golfer turns 100° towards his ball
<u>That </u><u>is</u><u>, </u>Angle = 100°
The golfer peces off 30 yards to his ball
<u>That </u><u>is</u><u>, </u>Base = 30 yards

<u>According </u><u>to </u><u>the </u><u>law </u><u>of </u><u>cosine </u><u>:</u><u>-</u>

$\bold{\red{ a^{2} = b^{2} + c^{2} - 2ABcos}}{\bold{\red{\theta}}}$

Here, a = perpendicular height
b = base
c = hypotenuse
cos theta = Angle of cosine

<u>So</u><u>, </u><u> </u><u>For </u><u>Hypotenuse </u><u>law </u><u>of </u><u>cosine </u><u>will </u><u>be </u><u>:</u><u>-</u>

$\sf{ c^{2} = a^{2} + b^{2} - 2ABcos}{\sf{\theta}}$

<u>Subsitute </u><u>the </u><u>required </u><u>values</u><u>, </u>

$\sf{ x^{2} = (150)^{2} + (30)^{2} - 2(150)(30)cos}{\sf{100°}}$

$\sf{ x^{2} = 22500 + 900 - 900cos}{\sf{\times{\dfrac{5π}{9}}}}$

$\sf{ x^{2} = 22500 + 900 - 900( - 0.174)}$

$\sf{ x^{2} = 22500 + 900 + 156.6}$

$\sf{ x^{2} = 23556.6}$

$\bold{ x = 153.48\: yards }$

Hence, The distance between the ball and the center of green is 153.48 or 153.5 yards

5 0

2 years ago

Mandy used the graph to write the equation of the line it represents. She took these steps. 1. y−intercept = (0, 2) 2. Slope = r

Katyanochek1 [597]

Based on the information given about the equation, y will be 0.5x + 2.

<h3>How to illustrate the equation?</h3>

From the information given, it should be noted that the equation of the line it represents was given and the y intercept is = (0, 2).

The function to represent y will be:

y = mx + b

y = (1/2)x + 2

y = 0.5x + 2

In conclusion, y = 0.5x + 2.

Learn more about equations on:

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3 0

1 year ago

W + 4 = (-6) This is an algebra question and I don't get the negative

Arada [10]

Answer:

w = -10

Step-by-step explanation:

w + 4 = (-6)

Subtract 4 from each side

w+4-4 = -6-4

w = -10

7 0

2 years ago

Read 2 more answers

A regular decagon has a radius of 8 cm. what is the approximate area of the decagon? recall that a decagon is a polygon with 10

lianna [129]

The approximate area of the decagon with a side of 8cm comes to be 492.40 cm².

The side of the regular decagon = 8cm

<h3>What is a regular decagon?</h3>

A regular decagon is a polygon with 10 sides that are equal to each other.

The area of a regular decagon with side a is:

$A=\frac{5}{2} a^{2} \sqrt{5+2\sqrt{5} }$

So, the area A of the regular decagon with a side of 8cm:

$A=\frac{5}{2} 8^{2} \sqrt{5+2\sqrt{5} }$

$A=160\sqrt{5+2\sqrt{5} }$

A=492.40 cm²

Therefore, the approximate area of the decagon is 492.40 cm².

To get more about the decagon visit:

brainly.com/question/19899848

7 0

1 year ago