The ratio of 
= - 34
How to solve such questions?
Such Questions can be easily solved just by some Algebraic manipulations and simplifications. We just try to make our expression in the form which question asks us. This is the best method to solve such questions as it will definitely lead us to correct answers. One such method is completing the square method.
Completing the square is a method that is used for converting a quadratic expression of the form 
to the vertex form
. The most common application of completing the square is in solving a quadratic equation. This can be done by rearranging the expression obtained after completing the square: 
, such that the left side is a perfect square trinomial
= 
= 
(Completing Square method)
=
On comparing with the given equation we get
p = - 
and q = 
∴ = 
= - 34
Learn more about completing the square method here :
brainly.com/question/26107616
#SPJ4
Answer:
3/4
Step-by-step explanation:
7/28 have blue eyes
So 28-7=21
21/28 don't have blue eyes
21/28 simplified=3/4
Answer:
2(n-6)=12
(I went too far in my explanation; I'm not going to erase it because I think it is important to have an example on solving these)
Step-by-step explanation:
Twice the difference of a number and 6 is the same as 12.
Twice means 2 times
Difference means the result of subtracting something.
is the same as means equal to (=).
So we are given 2(n-6)=12.
You can start by dividing 2 on both sides are distributing 2 to terms in the ( ).
I will do it both ways and you can pick your favorite.
2(n-6)=12
Divide both sides by 2.
n-6 =6
Add 6 on both sides
n =12
OR!
2(n-6)=12
Distribute 2 to both terms in the ( )
2n-12=12
Add 12 on both sides
2n =24
Divide both sides by 2
n =12
Step-by-step explanation:
area of a parallelogram is b×h
2.4×1=2.4cm²
I would appreciate if my answer is chosen as a brainliest answer
Answer:
Step-by-step explanation:
![\log_23x+\log_23=2\\\\\bold{DOMAIN}:\\3x>0\to x>0\\\\\text{Use}\ \log_ab+\log_ac=\log_a(bc)\\\\\log_2\bigg[(3x)(3)\bigg]=2\\\\\log_29x=2\qquad\text{use}\ \log_ab=c\iff a^c=b\\\\\log_29x=\log_22^2\\\\\log_29x=\log_24\iff9x=4\qquad\text{divide both sides by 9}\\\\\dfrac{9x}{9}=\dfrac{4}{9}\\\\\boxed{x=\dfrac{4}{9}}\in \bold{DOMAIN}](https://tex.z-dn.net/?f=%5Clog_23x%2B%5Clog_23%3D2%5C%5C%5C%5C%5Cbold%7BDOMAIN%7D%3A%5C%5C3x%3E0%5Cto%20x%3E0%5C%5C%5C%5C%5Ctext%7BUse%7D%5C%20%5Clog_ab%2B%5Clog_ac%3D%5Clog_a%28bc%29%5C%5C%5C%5C%5Clog_2%5Cbigg%5B%283x%29%283%29%5Cbigg%5D%3D2%5C%5C%5C%5C%5Clog_29x%3D2%5Cqquad%5Ctext%7Buse%7D%5C%20%5Clog_ab%3Dc%5Ciff%20a%5Ec%3Db%5C%5C%5C%5C%5Clog_29x%3D%5Clog_22%5E2%5C%5C%5C%5C%5Clog_29x%3D%5Clog_24%5Ciff9x%3D4%5Cqquad%5Ctext%7Bdivide%20both%20sides%20by%209%7D%5C%5C%5C%5C%5Cdfrac%7B9x%7D%7B9%7D%3D%5Cdfrac%7B4%7D%7B9%7D%5C%5C%5C%5C%5Cboxed%7Bx%3D%5Cdfrac%7B4%7D%7B9%7D%7D%5Cin%20%5Cbold%7BDOMAIN%7D)
