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oee [108]
3 years ago
11

How is solving a literal equation similar to solving a standard equation??

Mathematics
1 answer:
timama [110]3 years ago
8 0

Sometimes you have a formula, such as something from geometry, and you need to solve for some variable other than the "standard" one. For instance, the formula for the perimeter P of a square with sides of length s is P = 4s. You might need to solve this equation for s, so you can plug in a perimeter and figure out the side length.

This process of solving a formula for a given variable is called "solving literal equations". One of the dictionary definitions of "literal" is "related to or being comprised of letters", and variables are sometimes referred to as literals. So "solving literal equations" seems to be another way of saying "taking an equation with lots of letters, and solving for one letter in particular."

At first glance, these exercises appear to be much worse than your usual solving exercises, but they really aren't that bad. You pretty much do what you've done all along for solving linear equations<span> and other sorts of equation; the only substantial difference is that, due to all the variables, you won't be able to simplify your answers as much as you're used to. </span>
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33.33%

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3 years ago
25^2 6^3 find prime factorization
valentinak56 [21]

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3 years ago
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Kim was walking down a rocky path. For 4 minutes, the elevation dropped at the same rate. Altogether it dropped 8 feet. What was
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If Kim dropped for a total of 8 feet over the course of 4 minutes, then 8 feet/4 min equals 2 ft/min, but because they are dropping it should be negative.

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3 years ago
Given a term in an arithmetic sequence and the common difference, find the first five terms
andriy [413]

Answer:

Step-by-step explanation:

To find the first five terms

we come with a1

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a(17) = a1 +(17-1)6=71

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a(3) = -25 +(3-1)6=<u>-13</u>

a(4) = -25 +(4-1)6=<u>-7</u>

a(5) = -25 +(5-1)6=<u>-1</u>

<u>hope it helps</u>

<u />

 

5 0
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How would i find the measurement of angle 1 &amp; 2
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Check the picture below.

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