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oee [108]
2 years ago
11

How is solving a literal equation similar to solving a standard equation??

Mathematics
1 answer:
timama [110]2 years ago
8 0

Sometimes you have a formula, such as something from geometry, and you need to solve for some variable other than the "standard" one. For instance, the formula for the perimeter P of a square with sides of length s is P = 4s. You might need to solve this equation for s, so you can plug in a perimeter and figure out the side length.

This process of solving a formula for a given variable is called "solving literal equations". One of the dictionary definitions of "literal" is "related to or being comprised of letters", and variables are sometimes referred to as literals. So "solving literal equations" seems to be another way of saying "taking an equation with lots of letters, and solving for one letter in particular."

At first glance, these exercises appear to be much worse than your usual solving exercises, but they really aren't that bad. You pretty much do what you've done all along for solving linear equations<span> and other sorts of equation; the only substantial difference is that, due to all the variables, you won't be able to simplify your answers as much as you're used to. </span>
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PLEASE HELP I NEED A GOOD GRADE ON THIS
VladimirAG [237]

Answer:

B = 1/243

Step-by-step explanation:

6 0
3 years ago
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Help me please, the question is in the picture^^^!
Nat2105 [25]

Answer:

79.3

Step-by-step explanation:

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7 0
3 years ago
Consider the example of finding the probability of selecting a black card or a 6 from a deck of 52 cards.
Marina86 [1]

Answer:

The probability of selecting a black card or a 6 = 7/13

Step-by-step explanation:

In this question we have given two events. When two events can not occur at the same time,it is known as mutually exclusive event.

According to the question we need to find out the probability of black card or 6. So we can write it as:

P(black card or 6):

The probability of selecting a black card = 26/52

The probability of selecting a 6 = 4/52

And the probability of selecting both = 2/52.

So we will apply the formula of compound probability:

P(black card or 6)=P(black card)+P(6)-P(black card and 6)

Now substitute the values:

P(black card or 6)= 26/52+4/52-2/52

P(black card or 6)=26+4-2/52

P(black card or 6)=30-2/52

P(black card or 6)=28/52

P(black card or 6)=7/13.

Hence the probability of selecting a black card or a 6 = 7/13 ....

7 0
3 years ago
Help please!!!!;;;;;;;;;;;;;;;;;;;;
kozerog [31]

Hey!

-----------------------------------------------

Solution:

= (-18) - (4)

= -18 - 4

= -22

When you subtract a positive to a negative number the end result will always be negative.

-----------------------------------------------

Answer:

B. 22

-----------------------------------------------

Hope This Helped! Good Luck!

3 0
3 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
4vir4ik [10]
I hope this helps you

8 0
2 years ago
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