Answer:
Step-by-step explanation:
bruh
Multiply 4.93m by 8.5m to get 41.905m to the second power.
You do this because there are 2 identical triangles on the top. And if you put those two triangles together, you get a rectangle. The length of the rectangle is 8.5m while the width would be 4.93. Multiplying the length and width gives you the area.
Then multiply 10.2m by 8.5m to get 86.7m to the second power.
You do this because there are 2 identical triangles on the bottom. And if you put those two triangles together, you get another rectangle. The length of the rectangle is 8.5m while the width would be 10.2m. Multiplying those together gives you the area.
You then add the two areas, 41.905m to the second power and 86.7m to the second power, to get the area of the entire figure.
After adding, you get 128.605 m to the second power. That's the answer
Answer:
π(6 cm) (10 cm)
Step-by-step explanation:
As we know that
The formula to calculate the lateral surface area of the cone is πrl
where
r denotes the radius i.e. 6 cm
l denotes the length i.e. 10 cm
So based on the above information
The expression that shows the lateral surface area of the cone is
π(6 cm) (10 cm)
Therefore the third option is correct
Hence, the same would be relevant
First, you need to change it from standard form to slope-intercept form. To do this, you have to add 3x to both sides. Now that y is by itself, divide by 5 on both sides. Your equation should now be y=3x+3. Then, graph the points. Your x-intercept should be at (-5,0) and your y- intercept should be at (0,3).
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Let w represent the width, hence:
length = w + 33, height = w - 13
Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w
V(w) = w³ + 20w² - 429w
Rate of change = dV/dw = 3w² + 40w - 429
When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423
When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118
Rate = 10118 - 5423 = 4695 in³/in
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
Find out more on equation at: brainly.com/question/2972832
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