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Tasya [4]
2 years ago
13

Jordan made 8th blankets with 136 yard of material how many yards of material does she need to make 23 blanket​

Mathematics
2 answers:
prisoha [69]2 years ago
4 0
The answer is three hundred ninety one
miss Akunina [59]2 years ago
3 0

Answer:

391 yds of material

Step-by-step explanation:

to find the answer, you take 136 yards divided by 8 blankets, which equals 17.

Next, you multiply 23 blankets by that 17.

Then you find your answer, 391 yds.

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What is 1/10th of 2,871,000?
abruzzese [7]
This is fairly simple. Divide 2,871,000 by 10 and that's your answer!

\frac{2,871,000}{10} =287,100

Also, since you're dividing by a factor of 10 (or in this case, <em>10</em>) you can just take away as many places as are zeros in the number you're dividing from. This works for <em>10, 100, 1,000, 10,000, etc. </em>In this case, since there is only one zero in 10 you only take away one place marking, which gives you 287,100.
7 0
3 years ago
Help!!! I’ll give brainliest
MrMuchimi

Answer:

B

Step-by-step explanation:

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2 years ago
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podryga [215]
1. Combining like terms
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2 years ago
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The weights of packs of chewing gum for a certain brand have a mean of 47.1 grams and a standard deviation 2.4
Verdich [7]

A Z-score helps us to understand how far is the data from the mean. The correct option is B.

<h3>What is Z-score?</h3>

A Z-score helps us to understand how far is the data from the mean. It is a measure of how many times the data is above or below the mean. It is given by the formula,

Z = \dfrac{X- \mu}{\sigma}

Where Z is the Z-score,

X is the data point,

μ is the mean and σ is the standard variable.

The weight of a randomly selected pack of gum has a z-score of 3.11. Therefore, The weight of this pack of gum is heavier than the mean weight by 3.11 standard deviations.

Hence, the correct option is B.

Learn more about Z-score:

brainly.com/question/13299273

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4 0
2 years ago
Which figure could be the result of dilation the trapezoid with a scale factor between 0 and 1​
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1

Step-by-step explanation:

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