What is the acceleration of a 12kg box being pushed with 60N of force?

4. Which statement summarizes the excerpt? *

Aleks [24]

A hope that can help

6 0

3 years ago

A rocket takes off from Earth's surface, accelerating straight up at 69.2 m/s2. Calculate the normal force (in N) acting on an a

goldenfox [79]

According to Newton's 3rd law, there will be equal and opposite force on the astronaut which is -6048 N

<h3>What does Newton's third law say ?</h3>

The law state that in every action, there will be equal and opposite reaction.

Given that a rocket takes off from Earth's surface, accelerating straight up at 69.2 m/s2. We are to calculate the normal force (in N) acting on an astronaut of mass 87.4 kg, including his space suit.

Let us first calculate the force involved in the acceleration of the rocket by using the formula

F = ma

Where mass m = 87.4 kg, acceleration a = 69.2 m/s2

Substitute the two parameters into the formula

F = 87.4 x 69.2

F = 6048.08 N

According to the Newton's 3rd law, there will be equal and opposite force on the astronaut.

Therefore, the normal force acting on the astronaut is -6048 N approximately

Learn more about forces here: brainly.com/question/12970081

#SPJ1

7 0

2 years ago

A person walks 12 meters to the west and then 16 meters back to the east. what is the distance covered and the direction of disp

devlian [24]

The distance is 28 meters and the direction of displacement is East I think

6 0

3 years ago

The diagram shows two forces of equal magnitude acting on an object. If the common magnitude of the forces is 3.6 N and the angl

Nuetrik [128]

<h3>Answer</h3>

6.6 N pointing to the right

<h3>Explanation</h3>

Given that,

two forces acting of magnitude 3.6N

angle between them = 48°

To find,

the third force that will cause the object to be in equilibrium

Find the vertical and horizontal components of the two forces

vertical force1 = sin(24)(3.6)

vertical force2= -sin(24)(3.6)

<em>(negative sign since it is acting on opposite direction)</em>

vertical force3 = sin(24)(3.6) - sin(24)(3.6)

= 0

horizontal force1 = cos(24)(3.6)

horizontal force2= cos(24)(3.6)

horizontal force3 = cos(24)(3.6) + cos(24)(3.6)

= 2(cos(24)(3.6))

= 6.5775 N

≈ 6.6 N

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4 0

4 years ago

A battery is connected to the two ends of a conducting rod and the current through it is measured.a) Another rod, made of the sa

IceJOKER [234]

Answer:

a) - the resistance is proportional to the length of the metal

- a thicker rod, since resistance decreases with increasing area

b) The current is proportional to the area so this is the factor that is influenced by the electric field

Explanation:

a) When the rod is connected to the rod an electrical circuit described by the expression is formed

V = I R

I = V / R

The resistance of the rod is

R = ρ L / A

Where ρ is the resistivity of metal, L Longitud and A cross section.

If a higher current is measured when the other rod is connected, it implies that the resistance has decreased. To have a decrease in resistance you have two possibilities

- use a shorter rod, since the resistance is proportional to the length of the metal

- Use a thicker rod, since resistance decreases with increasing area, remember that the area of a circle is

A = π R²

Therefore, small increases in the diameter of the rod could give great changes in resistance.

b) The current is defined with the charge that crosses a surface per unit of time, when the electric field increases the electrons feel a greater force, therefore the current increases.

The charge number on a wire is

Q = q n $v_{d}$ Δt A

So up to date is

I = q n When the rod is connected to the rod an electrical circuit described by the expression is formed

V = I R

I = V / R

The resistance of the rod is

R = rho L / A

Where rho is the resistivity of metal, L e; Long and A cross section.

If a higher current is measured when the other rod is connected, it implies that the resistance has decreased. To have a decrease in resistance you have two possibilities

.- use a shorter rod, since the resistance is proportional to the length of the metal

. - Use a thicker rod, since resistance decreases with increasing area, remember that the area of a circle is

A = pi R2

Therefore, small increases in the diameter of the rod could give great changes in resistance.

.b) The current is defined with the charge that crosses a surface per unit of time, when the electric field increases the electrons feel a greater force, therefore the current increases.

The load number on a wire is

Q = q n $v_{d}$ Dt A

So current is

I = q n v_{d} A

The drag speed (v_{d}) is constant in the materials, it depends on the purity and imperfections, so a change in the length does not significantly change the current.

The current is proportional to the area so this is the factor that is influenced by the electric field

The drag speed (vd) is constant in the materials, it depends on the purity and imperfections, so a change in the length does not significantly change the current.

The current is proportional to the area so this is the factor that is influenced by the electric field

8 0

3 years ago