1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
IgorC [24]
3 years ago
11

Evaluate 5x-[21-(3-11)x] when x=-2​

Mathematics
1 answer:
mart [117]3 years ago
3 0

Answer:

-15

Step-by-step explanation:

(5)(−2)−(21−(3−11)(−2))

=−15

HAve a wonderful day Brainliest Please.

You might be interested in
The population is approximately 280,000 in 2006. The population grows at a rate of 7% per year. What was the population in 1990?
KonstantinChe [14]

Answer:

586,455 people

Step-by-step explanation:

im not sure

5 0
3 years ago
4√6 •√3 how do I show work for this because the answer is 2√12​
Yuliya22 [10]

Answer:

4 \sqrt{6}  \times  \sqrt{3}  = 12 \sqrt{2}

Step-by-step explanation:

We want to simplify the radical expression:

4 \sqrt{6}  \times  \sqrt{3}

We write √6 as √(2*3).

This implies that:

4 \sqrt{6}  \times  \sqrt{3}  = 4 \sqrt{2 \times 3}   \times  \sqrt{3}

We now split the radical for √(2*3) to get:

4 \sqrt{6}  \times  \sqrt{3}  = 4 \sqrt{2}  \times  \sqrt{3}  \times  \sqrt{3}

We obtain a perfect square at the far right.

4 \sqrt{6}  \times  \sqrt{3}  = 4 \sqrt{2}  \times  (\sqrt{3} )^{2}

This simplifies to

4 \sqrt{6}  \times  \sqrt{3}  = 4 \sqrt{2}  \times 3

This gives us:

4 \sqrt{6}  \times  \sqrt{3}  = 4 \times 3 \sqrt{2}

and finally, we have:

4 \sqrt{6}  \times  \sqrt{3}  = 12 \sqrt{2}

5 0
3 years ago
Leon wants to estimate the proportion of the seniors at his high school who like to watch football. He interviews a simple rando
cupoosta [38]

Answer:

Yes, the random conditions are met

Step-by-step explanation:

From the question, np^ = 32 and n(1 − p^) = 18.

Thus, we can say that:Yes, the random condition for finding confidence intervals is met because the values of np^ and n(1 − p^) are greater than 10.

Also, Yes, the random condition for finding confidence intervals is met because the sample size is greater than 30.

Confidence interval approach is valid if;

1) sample is a simple random sample

2) sample size is sufficiently large, which means that it includes at least 10 successes and 10 failures. In general a sample size of 30 is considered sufficient.

These two conditions are met by the sample described in the question.

So, Yes, the random conditions are met.

5 0
3 years ago
Whats the difference of 2 times d minus 3
Dmitriy789 [7]

Answer:

2(d - 3) is the equation. You cannot solve for d. You can only simplify it

7 0
3 years ago
What is equivalent to 2 5/6<br><br> A) 12/5<br> B) 17/6<br> C) 5/3<br> D) 7/6
KatRina [158]

B) 17/6

First I multiply 2 times 6 which gave me 12 then I added 12 plus 5 which gave me 17 then I used the number at the bottom which is 6 so the final answer was 17/6

5 0
3 years ago
Other questions:
  • Candice enjoys eating foods high in vitamin C to stay healthy. On Saturday, she ate 4 clementines and 7 kiwis for a total of 732
    15·1 answer
  • Donna is planning to take a trip to Spain that will cost $2,927. She has already saved $1,852. To earn the rest of the money, Do
    15·1 answer
  • mine is running the family fun fair at school he collected about $65 in donations each month for the seven months he was plannin
    14·1 answer
  • A movie theater problem I need help with
    5·1 answer
  • Can someone please give me a brianliest ?<br> sorry if I'm asking too much
    5·1 answer
  • Pls help with these asap
    8·1 answer
  • PLEASE!!! HELP!!!! PLEAE!!! WILL MARK AS BRAINLIEST!!!! PLEASE HELP!!!
    10·1 answer
  • Susan's fish tank has 16 liters of water in it. She plans to add 4 liters per minute until the tank has at least 64 liters. What
    8·1 answer
  • The area of a square photo frame is 100 cm^2 find the length of the photo frame
    15·2 answers
  • HELP
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!