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galina1969 [7]
2 years ago
15

QUICKKKKKKKKFor what values of a is the sum of the fractions (2a−1)/4 and (a−1)/3 positive?

Mathematics
1 answer:
nordsb [41]2 years ago
7 0

Answer:

a>\frac7{10}

Step-by-step explanation:

\frac{2a-1}4+\frac{a-1}3>0\ \ \ \ \ |\cdot 12\\ 12\cdot\frac{2a-1}4+12\cdot\frac{a-1}3>12\cdot0\\ 3(2a-1)+4(a-1)>0\\ 6a-3+4a-4>0\\ 10a-7>0\\ 10a>7\ \ \ \ |:10\\ a>\frac7{10}

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yawa3891 [41]

Answer:

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Step-by-step explanation:

3 0
2 years ago
Which expression is equivalent to 6a + 15? A. 6(a + 5) B. 3(2a + 5) C. 3(3a + 12) D. 6(a + 12) PLEASE HELP :)
makvit [3.9K]
The answer is B

A. 6(a+5)
=6a+30 not equivalent to 6a+15
B.3(2a+5)
=6a+15 is equivalent
C.3(3a+12)
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D.6(a+12)
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So your answer is B
4 0
3 years ago
Read 2 more answers
A bacteria colony increases in size at a rate of 4.0581e1.6t bacteria per hour. If the initial population is 36 bacteria, find t
Harrizon [31]

Answer:

1560

Step-by-step explanation:

The rate of Increase of the population (P) of the bacteria is given as:

\frac{dP}{dt} =4.058e^{1.6t}

dP =4.058e^{1.6t}}dt\\Taking\: Integrals\\\int dP =4.058 \int e^{1.6t}dt\\P(t)=\frac{4.058}{1.6} (e^{1.6t} +K)\\P(t)=2.53625 (e^{1.6t} +K)

Where k is a constant of Integration.

At t=0, P(t)=36

36=2.53625 (e^{1.6*0} +K)\\36=2.53625 (e^{0} +K)\\36=2.53625 (1 +K)\\36=2.53625 +2.53625K\\K=13.19

Therefore:

P(t)=2.53625 (e^{1.6t} +13.19)\\At \: t=4\\P(4)=2.53625 (e^{1.6*4} +13.19)\\=1559.88\\P(4)=1560

3 0
3 years ago
67. Find all points on the x-axis that are 5 units from the point<br> (4, -3).
Setler [38]

Answer:(9,2) I assume I don’t really understand the question

Step-by-step explanation:

5 0
2 years ago
Sandy bought a soft drink for 4 dollars and 9 candy bars. She spent
almond37 [142]
9c + 4 = 49

The numbers by themselves represent the amount of dollars spent (4 and 49), but since you don’t know the amount of money each candy bar cost, you would put the amount of candy bars and a variable next to it to then solve ($5 per bar)
5 0
3 years ago
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