Question

QUICKKKKKKKKFor what values of a is the sum of the fractions (2a−1)/4 and (a−1)/3 positive?

Answer 1

Answer:

$a>\frac7{10}$

Step-by-step explanation:

$\frac{2a-1}4+\frac{a-1}3>0\ \ \ \ \ |\cdot 12\\ 12\cdot\frac{2a-1}4+12\cdot\frac{a-1}3>12\cdot0\\ 3(2a-1)+4(a-1)>0\\ 6a-3+4a-4>0\\ 10a-7>0\\ 10a>7\ \ \ \ |:10\\ a>\frac7{10}$