<u>Given:</u>
Number of pages read by Jack = 40 per hour
Rate of reading by Dave =3/5 of a page in a minute
<u>To find:</u>
The person who reads faster and by how many minutes.
<u>Solution:</u>
If Dave reads 3/5 of a page in a minute then in an hour he would read,
(60 minutes = 1 hour)
pages in an hour
The difference between pages read by Jack and Dave is
Therefore, Jack reads faster than Dave by 4 pages.
I am going to do the first 2 problems and show my work that way you know how to do it yourself.
So first of all, the foil method:
(a+b) (c+d) = ac+ad+bc+bd
1. (3xy-1) (4xy+2) = (3xy*4xy) + (3xy*2) + (-1*4xy) + (-1*2)
(3xy-1) (4xy+2) = (12x^2y^2) + (6xy) + (-4xy) + (-2)
(3xy-1) (4xy+2) = (12x^2y^2) + (6xy-4xy) - 2
(3xy-1) (4xy+2) = 12x^2y^2 + 2xy - 2
2. <span>(2x-3y) (4x-y) = (2x*4x) + (2x*-y) + (-3y*4x) + (-3y*-y)
(2x-3y) (4x-y) = (8x^2) + (-2xy) + (-12xy) + (3y^2)
</span> (2x-3y) (4x-y) = 8x^2 + (-2xy-12xy) + 3y^2
(2x-3y) (4x-y) = 8x^2 - 14xy + 3y^2
I hope this helps!
=>3q+5+2q-5 = 65
=>3q + 2q +5 - 5 - 65 = 0
=>5q -65 =0
=>5q = 65
=>q = 65/5
=>q= 13..
=>so the answer is option B (q=13)..
Hope it helps !!!
Answer:
Can u get closer?
Step-by-step explanation:
I cant see