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just olya [345]
3 years ago
15

Xina has $289 and spends $55 at the grocery

Mathematics
1 answer:
Kruka [31]3 years ago
6 0
200 dollars like the answer please
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Range of the function f(x) = -x^2 - 5
Naddik [55]

Answer:

Step-by-step explanation:

6 0
3 years ago
-11.
dalvyx [7]

Answer:

<em>A(2,3) has a distance of 2 to the y-axis</em>

<em>B(-3,2) has a distance of 3 to the y-axis</em>

<em>C(2,-3) has a distance of 2 to the y-axis</em>

<em>D(-3,-2) has a distance of 3 to the y-axis</em>

Step-by-step explanation:

<u>Distance of a point to an axis</u>

Given a point (x,y) its rectangular coordinates are defined as the distances from the point to each axis with respect to the origin (0,0).

For example, the point (5,4) has a distance of 5 from the y-axis and a distance of 4 from the x-axis.

Generally speaking, point (x,y) has a distance |x| from the y-axis and a distance |y| from the x-axis.

The absolute value bars are used because the distance is always positive.

Apply that to the points:

A(2,3) has a distance of 2 to the y-axis

B(-3,2) has a distance of 3 to the y-axis

C(2,-3) has a distance of 2 to the y-axis

D(-3,-2) has a distance of 3 to the y-axis

8 0
2 years ago
Find three consecutive integers whose sum is 48
mart [117]

Answer:

our numbers should be 15, 16, and 17.

Step-by-step explanation:

n + n+1 + n+2 = 48.

8 0
3 years ago
Problem 1.(32 points) A random sample of 100 Uber rides in Chicago has on average 5.4miles per ride. Assume the distribution of
marshall27 [118]

Answer:

a) CI = ( 5,1 ; 5,7 )

b) SE =  0,1  

Step-by-step explanation:

a) Sample random     n  = 100

Mean  =  μ = 5,4

Standard deviation   s = 1,3

CI = 99 %    α = 1 %   α = 0,01     α/2 =  0,005

z(c) for  0,005 is from z-table    z(c)  = 2,575

z(c)  =  ( X - μ ) /s/√n          CI  =  μ ± z(c) * s/√n

CI =  5,4 ± 2,575* 1,3/10

CI = 5,4 ± 0,334

CI = ( 5,1 ; 5,7 )

b) SE = Standard deviation / √n

SE = 1,3 /10       SE =  0,1  

We can support that with 99 % of probability our random variable will be in the CI.

6 0
2 years ago
Ln (x-2) +ln (2x-3)=2ln x
goblinko [34]
D:x-2\ \textgreater \ 0 \wedge 2x-3\ \textgreater \ 0 \wedge x\ \textgreater \ 0\\&#10;D:x\ \textgreater \ 2 \wedge x\ \textgreater \ \dfrac{3}{2}\wedge x\ \textgreater \ 0\\&#10;D:x\ \textgreater \ 2\\\\&#10;\ln (x-2) +\ln (2x-3)=2\ln x \\&#10;\ln (x-2)(2x-3)=\ln x^2\\&#10;(x-2)(2x-3)=x^2\\&#10;2x^2-3x-4x+6=x^2\\&#10;x^2-7x+6=0\\&#10;x^2-x-6x+6=0\\&#10;x(x-1)-6(x-1)=0\\&#10;(x-6)(x-1)=0\\&#10;x=6 \vee x=1\\&#10;1\not \in D\\&#10;\boxed{x=6}
4 0
3 years ago
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