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just olya [345]
3 years ago
15

Xina has $289 and spends $55 at the grocery

Mathematics
1 answer:
Kruka [31]3 years ago
6 0
200 dollars like the answer please
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Apples come in bags of 4. Oranges come in bags of 6.
muminat

Answer: Apples come in bags of 4. Oranges come in bags of 6.

so it going to be Multiple 4x6=24 I explain it, is this how you want it

Step-by-step explanation: hope this help

3 0
3 years ago
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Which would be a good statistical question Alexandra could have used to create the tally chart?
Roman55 [17]

Answer: D

Step-by-step explanation:

Sorry I’m late.

Remember:

A STATISTICAL QUESTION has variable answers.

Ex: How many toys are in the U.S?

A NON-STATISTICAL QUESTIONS have only one answer

4 0
3 years ago
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Question 5- Please help. Using a piece of pizza explain what arc length and area of the sector mean in two to three sentences.
pickupchik [31]

Answer:

You'd have to look at the size of the pizza and then measure the size of the arc for each slice. The slice of pizza is how many topping is on it. The sector is how much pizza you are consuming from the center to the crust. The arc is the crust around the pizza.

3 0
3 years ago
Helppppppppppppooppppoopp
Lyrx [107]

Answer:

Let x rep the lenght of the shorter one

Then the longer one is 2x+1

Therefore

(2x+1) + x = 16

We now solve for x

2x + 1 + x = 16

Group and evaluate like terms

3x +1 = 16

3x = 16 -1

× = 15/3

x = 5

So the shorter one is 5 ft

The longer one is 2(5)+1= 11

4 0
3 years ago
En una fiesta hay 40 asistentes de los cuales el número de varones que no bailan es el doble que el número de las mujeres que no
Arte-miy333 [17]

Answer:

50%

Step-by-step explanation:

Para resolver este problema vamos a definir 4 variables:

V= número de varones bailando.

M= número de mujeres bailando.

V' = número de varones que no están bailando.

M' = número de mujeres que no están bailando.

Sabemos que hay 40 personas en la fiesta, por lo que podemos construir la siguiente ecuación:

V+M+V'+M'=40

Vamos a suponer que cada mujer que está bailando, está bailando varón respectivamente. (El problema no da más información, entonces podemos suponer esto.)

Entonces si hay 5 mujeres bailando, entonces también hay 5 hombres bailando, por lo que nuestra ecuación se reescribe de la siguiente manera:

5+5+V'+M'=40

y simplificamos:

10+V'+M'=40

V'+M'=40-10

V'+M'=30

Ahora bien, el problem nos dice que el número de varones que no bailan es el doble del número de mujeres que no bailan en un determinado momento. Entonces con esta información podemos construir la siguiente ecuación:

V'=2M'

Y podemos despejar el número de mujeres que no bailan, lo que nos da:

M'=\frac{V'}{2}

Entonces podemos sustituir esto dentro de nuestra ecuación para obtener:

\frac{V'}{2}+V'=30

y podemos entonces despejar V'

\frac{3V'}{2}=30

V'=\frac{2(30)}{3}

V'=20

Entonces hay 20 varones que no están bailando, por lo que la probabilidad de que el varón que se escoge al azar no esté bailando está dada por la siguiente fórmula:

P=\frac{V'}{total}

P=\frac{20}{40}=\frac{1}{2}

P=50%

6 0
2 years ago
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