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PIT_PIT [208]
2 years ago
12

(a^3 b^12 c^2) * (a^5 c^2) * (b^5 c^4)^0

Mathematics
1 answer:
trapecia [35]2 years ago
3 0

Step-by-step explanation:

= ( {a}^{3}  {b}^{12} {c}^{2}  ) \times ( {a}^{5} {c}^{2}  ) \times ( {b}^{5}  {c}^{4} ) {}^{0}

=  {a}^{3 + 5}  {b}^{12}  {c}^{2 + 2}

=  {a}^{8}  {b}^{12}  {c}^{4}

Option D

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marissa [1.9K]

Answer:

x = 28.01t,

y = 10.26t - 4.9t^2 + 2

Step-by-step explanation:

If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -

x = ( 30 cos 20° )( time ),

y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2

To determine " ( 30 cos 20° )( time ) " you would do the following calculations -

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This represents our horizontal distance, respectively the vertical distance should be the following -

y = 30 * 0.34 - 4.9t^2,

( y = ( About ) 10.26t - 4.9t^2 + 2

In other words, our solution should be,

x = 28.01t,

y = 10.26t - 4.9t^2 + 2

<u><em>These are are parametric equations</em></u>

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3 years ago
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