Answer:
0.492 J/g °C
General Formulas and Concepts:
<u>Thermodynamics</u>
Specific Heat Formula: q = mcΔT
- <em>q</em> is heat (in J0
- <em>m</em> is mass (in g)
- <em>c</em> is specific heat (in J/g °C)
- <em>ΔT</em> is change in temperature (in °C)
Explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
[Given] <em>q</em> = 45.0 J
[Given] <em>m</em> = 8.10 g
[Given] <em>ΔT</em> = 24.3 °C - 13.0 °C = 11.3 °C
[Solve] <em>c</em>
<em />
<u>Step 2: Solve for </u><em><u>c</u></em>
- Substitute in variables [Specific Heat Formula]: 45.0 J = (8.10 g)c(11.3 °C)
- Multiply: 45.0 J = (91.53 g °C)c
- Isolate <em>c</em>: 0.491642 J/g °C = c
- Rewrite: c = 0.491642 J/g °C
<u>Step 3: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.491642 J/g °C ≈ 0.492 J/g °C
Solid - Retains its shape no matter the container
Gas - Particles move freely but dont go far
Liquid - Expands to fit the volume of container
Plasma - I guess the oter thing
(THEESE ARE JUST EDUCATED GUESSES)
You may recall that gamma radiation is at the far right (high energy) end of the electromagnetic spectrum. Because of its high energy level, gamma radiation has the greatest penetrative power.
Two or more compounds that have same molecular formula but differ in the arrangement of atoms in molecule and thus posses different properties are known as isomers.
The molecular formula of pentane is 
substituting one hydrogen from pentane with bromine results in the formation of monobromo derivatives of pentane having molecular formula, 
.
The structure of monobromo derivatives of pentane that is 1-bromopentane, 2-bromopentane, and 3-bromopentane and having molecular formula, is shown in the image.
The other two arrangements of monobromo derivatives of pentane that is 2-bromo-2-methylbutane and 2-bromo-3-methylbutane is shown in the image.
There are different structures of monobromo derivatives of pentane having molecular formula, which contain a 4-carbon chain are 1- bromo-2-methylbutane and 1-bromo-3-methylbutane shown in the image.
