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MArishka [77]
3 years ago
12

It takes 45.0 J to raise the temperature of an 8.10 g piece of unknown metal from 13.0∘C to 24.3 ∘C. What is the specific heat f

or the metal?
Chemistry
1 answer:
hodyreva [135]3 years ago
5 0

Answer:

0.492 J/g °C

General Formulas and Concepts:

<u>Thermodynamics</u>

Specific Heat Formula: q = mcΔT

  • <em>q</em> is heat (in J0
  • <em>m</em> is mass (in g)
  • <em>c</em> is specific heat (in J/g °C)
  • <em>ΔT</em> is change in temperature (in °C)

Explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] <em>q</em> = 45.0 J

[Given] <em>m</em> = 8.10 g

[Given] <em>ΔT</em> = 24.3 °C - 13.0 °C = 11.3 °C

[Solve] <em>c</em>

<em />

<u>Step 2: Solve for </u><em><u>c</u></em>

  1. Substitute in variables [Specific Heat Formula]:                                             45.0 J = (8.10 g)c(11.3 °C)
  2. Multiply:                                                                                                             45.0 J = (91.53 g °C)c
  3. Isolate <em>c</em>:                                                                                                            0.491642 J/g °C = c
  4. Rewrite:                                                                                                             c = 0.491642 J/g °C

<u>Step 3: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.491642 J/g °C ≈ 0.492 J/g °C

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