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3 years ago

Which type of emission has the highest penetrating power?

1 answer:

7 0

You may recall that gamma radiation is at the far right (high energy) end of the electromagnetic spectrum. Because of its high energy level, gamma radiation has the greatest penetrative power.

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Someone please do this!!!

Lilit [14]

Answer:

1) Fe = 69.9%

O = 31.1%

2) H = 5.19%

O = 16.5%

N = 28.9%

C = 49.5%

Explanation:

One easy way to do percent compositions is to assume you have 100g of a substance.

1) Lets say we have 100g of Fe2O3.

The total molar mass would be:

$= 55.845*2+15.999*3 = 159.687$

The molar mass of the Fe2 alone is:

$=55.845*2 = 111.69$

Thus, the grams of Fe2(out of a 100) could be calculated by multiplying 100g * the molar mass ratio of Fe2 to the whole:

$= 100g *\frac{111.69}{159.687} = 69.9431$

Which is approximately 69.9%.

We can find the amount of O3 by simply subtracting, as the rest of the compound is made of O3. Thus, the % composition of O3 is 31.1%

You can then do this same process to the next question, getting us the following:

H = 5.19%

O = 16.5%

N = 28.9%

C = 49.5%

4 0

3 years ago

Consider the following balanced equation:

algol [13]

Moles of PF₃ : 4

<h3>Further explanation</h3>

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

$\tt P_4(s)+6F_2(g)\rightarrow 4PF_3(g)$

1.25 moles of P₄(s) is reacted with 6 moles of F₂(g)

Limiting reactant : the smallest ratio (mol divide by coefficient)

P₄ : F₂ =

$\tt \dfrac{1.25}{1}\div \dfrac{6}{6}=1.25\div 1\rightarrow F_2~limiting~reactant(smallest~ratio)$

mol PF₃ based on mol of limiting reactant(F₂), so mol PF₃ :

$\tt \dfrac{4}{6}\times 6~moles=4~moles$

8 0

3 years ago

Sodium, Na, is a metallic element.

Vladimir79 [104]

Answer:

metallic bonding is the bond form between two or more metal elements or between metal element and the other group elements

5 0

2 years ago

A researcher placed 25.0 g of silver chloride, AgCl, in sunlight and allowed the substance to decompose completely to form silve

steposvetlana [31]

Answer:

A. The law of definite proportions states that all pure samples of a particular chemical compound contain the same elements combines in the same proportion by mass.

B. The law of conservation of mass states that during ordinary chemical reactions, matter can neither be created or destroyed.

Note: The full question is as follows;

A researcher placed 25.0 g of silver chloride, AgCl, in sunlight and allowed the substance to decompose completely to form silver, Ag, with the release of chlorine gas, Cl2. The gas was collected in a container during the decomposition. The researcher determined that the mass of the silver formed was 18.8 g, and the mass of the chlorine gas formed was 6.2 g. The equation for the reaction is:

2AgCl ----> 2Ag + Cl2

a. State the law of definite proportions. Then use the researcher's data to confirm the law of definite proportions. Show your calculations.

b. State the law of conservation of matter. Then use the researcher's data to confirm the conservation of matter. Show your calculations.

Explanation:

A. Mass of silver obtained from AgCl = 18.8g.

Percentage mass of silver in the chloride = (18.8/25.0) * 100 = 75.2 %

Mass of chlorine obtained from AgCl = 6.2

Percentage mass of chlorine = (6.2/25) * 100 = 24.8 %

In one mole of AgCl with a molar mass of 143.3 g/mol; mass of silver = 107.8, mass of Cl = 35.5

Percentage mass of Ag = (107.8/143.3) * 100 = 75.2%

Percentage mass of Cl = (35.5/143.3) * 100 = 24.8%

Since the percentages by mass of Ag and AgCl obtained from the sample is the same to that obtained from a mole of AgCl, the law of definite proportions which states that all pure samples of a particular chemical compound contain the same elements combined in the same proportion by mass is verified.

B. Mass of reactant; AgCl sample = 25.0

Mass of products; At = 18.8 g; Cl = 6.2 g

Sum of products masses = 18.8 + 6.2 = 25.0 g

Therefore mass of reactant = mass of products.

This is in accordance with the law of conservation of mass which states that during ordinary chemical reactions, matter is neither created nor destroyed.

8 0

3 years ago

Based on this equation: 2AL + 3CuCl2 -> 2AlCl3 + Cu ... how many grams of copper(II) chloride dihydrate would be required to

PolarNik [594]

2Al + 3CuCl2 ➡ 2AlCl3 + 3Cu. Moles of Al = 1.2/27 = 0.045 moles 2 moles of Al reacts with 3 moles of CuCl2. Therefore, 1 mole of CuCl2 reacts with =2/3 x moles of Al = 2/3 x 0.045 = 0.03 moles.

6 0

3 years ago