It is used to separate an insoluble solute from a liquid.
It is normally filtered by using filter paper, the liquid that passes through the paper is called filtrate, meanwhile the insoluble particles and a bit liquid left on the filter paper is called residue.
We can also separate insoluble solute from liquid by decantation.
1) Chemical equation
2Al + 6 HCl ---> 2Al Cl3 + 3 H2
2) molar ratios
2 mol Al : 3 moles H2
3) Proportion
2 mol Al / 3mol H2 = x / 9 mol H2
4) Solve for x
x = 9 mol H2 * 2 mol Al / 3 mol H2 = 6 mol Ag
Answer: 6 moles
Answer: The molarity of the solution is 2.00 M
Explanation:
Molarity is defined as the number of moles of solute dissolved per liter of the solution.
![Molarity=\frac{n}{V_s}](https://tex.z-dn.net/?f=Molarity%3D%5Cfrac%7Bn%7D%7BV_s%7D)
where,
n = moles of solute
= volume of solution in L = 1.00 L
moles of solute =![\frac{\text {given mass}}{\text {molar mass}}=\frac{116.9g}{58.5g/mol}=2.00moles](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7Bgiven%20mass%7D%7D%7B%5Ctext%20%7Bmolar%20mass%7D%7D%3D%5Cfrac%7B116.9g%7D%7B58.5g%2Fmol%7D%3D2.00moles)
![Molarity=\frac{2.00mol}{1.00L}=2.00M](https://tex.z-dn.net/?f=Molarity%3D%5Cfrac%7B2.00mol%7D%7B1.00L%7D%3D2.00M)
Thus the molarity of the solution is 2.00 M