Answer:
615 centimeters
Step-by-step explanation:
Kate used 6.15 meters of ribbon to make a bow
The centimeters of the ribbon used by kate can be calculated as follows
1 meter=100 centimeters
6.15 meters= x
Cross multiply both sides
1 × x = 6.15 × 100
x = 615 centimeters
Hence Kate used 615 centimeters of the ribbon
Answer: X = -12
Step-by-step explanation: 1) 12 + x/4 = 9
2) 12 + x/ 2^2 = 9
3) x/ 2^2 + 12 = 9
Because the triangle with the legs 2 and 2 would need to have a third leg less than 4 and greater than 0 and a triangle with side lengths 2 and 4 would need a third side of less than 6 and greater than 2
1.146 pounds is the answer rounded to the thousandths place
Answer:
Step-by-step explanation:

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<u>Consider</u></h2>

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<u>W</u><u>e</u><u> </u><u>K</u><u>n</u><u>o</u><u>w</u><u>,</u></h2>




So, on substituting all these values, we get




<h2>Hence,</h2>

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<h2>ADDITIONAL INFORMATION :-</h2>
Sign of Trigonometric ratios in Quadrants
- sin (90°-θ) = cos θ
- cos (90°-θ) = sin θ
- tan (90°-θ) = cot θ
- csc (90°-θ) = sec θ
- sec (90°-θ) = csc θ
- cot (90°-θ) = tan θ
- sin (90°+θ) = cos θ
- cos (90°+θ) = -sin θ
- tan (90°+θ) = -cot θ
- csc (90°+θ) = sec θ
- sec (90°+θ) = -csc θ
- cot (90°+θ) = -tan θ
- sin (180°-θ) = sin θ
- cos (180°-θ) = -cos θ
- tan (180°-θ) = -tan θ
- csc (180°-θ) = csc θ
- sec (180°-θ) = -sec θ
- cot (180°-θ) = -cot θ
- sin (180°+θ) = -sin θ
- cos (180°+θ) = -cos θ
- tan (180°+θ) = tan θ
- csc (180°+θ) = -csc θ
- sec (180°+θ) = -sec θ
- cot (180°+θ) = cot θ
- sin (270°-θ) = -cos θ
- cos (270°-θ) = -sin θ
- tan (270°-θ) = cot θ
- csc (270°-θ) = -sec θ
- sec (270°-θ) = -csc θ
- cot (270°-θ) = tan θ
- sin (270°+θ) = -cos θ
- cos (270°+θ) = sin θ
- tan (270°+θ) = -cot θ
- csc (270°+θ) = -sec θ
- sec (270°+θ) = cos θ
- cot (270°+θ) = -tan θ