Step-by-step explanation:
A = A₀ ½^(t / T)
where A is the amount left, A₀ is the original amount, t is time, and T is the half life.
4 days is 96 hours, so the amount left is:
A = 600 ½^(96 / 15)
Answer:
Step-by-step explanation:
1. y = 2x
y = 2*4 = 8 Checks, therefore
y = 20 for x = 10
2. y = 3x
y = 3*(0.3) = 0.9 Checks, therefore:
y = 3*(1.5) = 4.5
y = 3*
3. y = 5/x
y = 5/(1/2) = 10 Checks, therefore:
3 = 5/x
x = 5/3
4 v = wu
7*3 = 21 Checks, therefore:
v = (3/4)*(6) = (18/4) = (9/2)
v = (2/3)wu
v = (2/3)*7*3 = 14 Checks
5 m = Kn/p [Add the K as a constant that will make m = Knp true at some value of K]
9 = K*2/(1/3)
27 = (K*2)
27 = 2K
K = (3/2)
m = (3/2) (n/p)
m = (3/2)*((1/2)/(1/3))
m = (3/2)*(3/2)
m = 1
x<_-4 or (-*infinity*,-4]
Step-by-step explanation:
Hmm, there are 5 letters
if you cannot repeat the letters
hmm, let's find how many for 4 letters
there are 4! or 4*3*2*1=24
that's how many ways there are to arrange a,b,c, d
now we can multiply it by 4 because there are 4 choices for the last place (e is not included0
24*4=56
answer is 56 different arrangements
Answer:
0.15 = 15%
Step-by-step explanation:
Let's call the recessive allele x, and the dominant allele X.
The homozygotes have the pair xx, and the heterozygotes have the pair Xx.
If two heterozygotes conceive a child, there are four configurations that the child can have:
xx, xX, Xx, XX
the only configuration that allows the child the possibility to have extra fingers and toes is the xx, as this aspect is a recessive trait, so the probability of the child being xx is 25% (1 option between 4 options, all of them with equal probabilities).
If the child is xx, there is a chance of 60% of the child having extra fingers and toes. So, the final probability is:
25% * 60* = 0.25 * 0.6 = 0.15 = 15%
