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krek1111 [17]
3 years ago
9

Solve the radical equation: 16- X = 4. -10 4 10 No Real Solution

Mathematics
1 answer:
Citrus2011 [14]3 years ago
3 0
6.5 simfmtriodngnrjdjfn
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Solve the equation for a.<br><br> 3a+13.61=−9.43
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Answer: a = -7.68

<u>STEPS:</u>

- Subtract 13.61 from both sides

- Simplify

- Divide both sides by 3

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Suppose that a wall is constructed from concrete blocks where a block is a normal random variable with mean 11 kg and standard d
Artemon [7]

Answer:

The value for <em>k</em> is about k = 11.093kg.

Step-by-step explanation:

To answer this question, that is, P(x<k) = 0.85, we can use the standardized value for a raw score, or the formula for obtaining z-scores:

\\ z = \frac{x - \mu}{\sigma} [1]

Where

\\ x is the raw score.

\\ \mu is the population mean.

\\ \sigma is the population standard deviation.

In this case, we are asking to find a value x = k, so that 85% of the blocks have weights less than k (kg).

We have also to use the values for the <em>cumulative standard normal distribution</em> with \\ \mu = 0 and \\ \sigma = 1 to find the value of z that corresponds to a probability of 0.85.

First step: find the z that corresponds to the probability of 0.85.

To use the formula [1], as we previously mentioned, we first need to find the value of <em>z</em> that corresponds to a probability of 0.85 using the <em>cumulative standard normal distribution table</em> (available in any Statistics books or on the Internet). Then, for a cumulative probability of 0.85, the corresponding value for z = 1.03 (approximately).

Second step: solve the formula [1] for x.

Solving this formula for x, we have:

\\ z = 1.03

\\ \mu = 11kg

\\ \sigma = 0.09kg

Then (without units):

\\ z = \frac{x - \mu}{\sigma}

\\ 1.03 = \frac{x - 11}{0.09}

\\ 1.03*0.09 = x - 11

\\ (1.03*0.09) + 11 = x

So

\\ x = (1.03*0.09) + 11

\\ x = 0.0927 + 11

\\ x = 11.0927 \approx 11.093 = k

Thus, this value for x = 11.093 equals the value for k (x = k) so that

\\ P(x

Then

\\ P(x or

\\ P(x

We can see the graph below showing this value of k = 11.093kg for which 85% of the blocks have weights less that it (x = k = 11.093kg).  

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Suppose there are eight different management trainee positions to be assigned to eight employees in a company’s junior managemen
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